gaspersic/freeCodeCamp
1
0
Fork 0
Code Issues Pull Requests Projects Releases Wiki Activity

Rewrite description of Pairwise bonfire. Added second test illustrating the no-reuse rule.

Browse Source
This commit is contained in:
Jonathan Boiser
2015-03-06 23:39:45 -08:00
parent 3416353baf
commit a6cd9876d9
1 changed files with 3 additions and 3 deletions
Download Patch File Download Diff File Expand all files Collapse all files

6
seed_data/bonfires.json
View File

@ -493,15 +493,15 @@
"name": "Pairwise",
"difficulty": "2.16",
"description": [
"Return the sum of all the indexes of elements that can be added to another element of the first array and equal the target provided in the second argument",
"Return the sum of all indices of elements of 'arr' that can be paired with one other element to form a sum that equals the value in the second argument 'arg'. If multiple sums are possible, return the smallest sum. Once an element has been used, it cannot be reused to pair with another.",
"For example, pairwise([1, 4, 2, 3, 0, 5], 5) should return 15 because every element can be paired with another element to equal 5.",
"pairwise([1, 3, 2, 4], 4) would only equal 1, because only the first two elements can be paired to equal 4, and the first element has an index of 0!",
"Once an element has been used it cannot be reused to pair with another."
"pairwise([1, 3, 2, 4], 4) would only equal 1, because only the first two elements can be paired to equal 4, and the first element has an index of 0!"
],
"challengeSeed": "function pairwise(arr, arg) {\n return arg;\n}\n\npairwise([1,4,2,3,0,5], 5);",
"tests": [
"expect(pairwise([1, 4, 2, 3, 0, 5], 5)).to.equal(15);",
"expect(pairwise([1, 3, 2, 4], 4)).to.equal(1);",
"expect(pairwise([1,1,1], 2)).to.equal(1);",
"expect(pairwise([0, 0, 0, 0, 1, 1], 1)).to.equal(10);",
"expect(pairwise([], 100)).to.equal(0);"
]