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fix(curriculum): Perform a Union on Two Sets (#34607)

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Aditya 2018-12-16 21:08:35 +05:30 committed by Kristofer Koishigawa
parent f9e9cb6dff
commit eae4363b76
1 changed files with 42 additions and 4 deletions
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46
curriculum/challenges/english/08-coding-interview-prep/data-structures/perform-a-union-on-two-sets.english.md
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@ -12,7 +12,6 @@ For example, if <code>setA = ['a','b','c']</code> and <code>setB = ['a','b','d',
## Instructions
<section id='instructions'>
</section>
## Tests
@ -22,8 +21,8 @@ For example, if <code>setA = ['a','b','c']</code> and <code>setB = ['a','b','d',
tests:
- text: Your <code>Set</code> class should have a <code>union</code> method.
testString: assert((function(){var test = new Set(); return (typeof test.union === 'function')})(), 'Your <code>Set</code> class should have a <code>union</code> method.');
- text: The proper collection was returned
testString: assert((function(){var setA = new Set(); var setB = new Set(); setA.add('a'); setA.add('b'); setA.add('c'); setB.add('c'); setB.add('d'); var unionSetAB = setA.union(setB); var final = unionSetAB.values(); return (final.indexOf('a') !== -1 && final.indexOf('b') !== -1 && final.indexOf('c') !== -1 && final.indexOf('d') !== -1 && final.length === 4)})(), 'The proper collection was returned');
- text: The union of <code>["a", "b", "c"]</code> and <code>["c", "d"]</code> should return <code>["a", "b", "c", "d"]</code>.
testString: assert((function(){var setA = new Set(); var setB = new Set(); setA.add('a'); setA.add('b'); setA.add('c'); setB.add('c'); setB.add('d'); var unionSetAB = setA.union(setB); var final = unionSetAB.values(); return (final.indexOf('a') !== -1 && final.indexOf('b') !== -1 && final.indexOf('c') !== -1 && final.indexOf('d') !== -1 && final.length === 4)})(), 'The union of <code>["a", "b", "c"]</code> and <code>["c", "d"]</code> should return <code>["a", "b", "c", "d"]</code>.');
```
@ -84,7 +83,46 @@ function Set() {
```js
function Set() {var collection = []; this.has = function(e){return(collection.indexOf(e) !== -1);};this.values = function() {return collection;};this.add = function(element) {if (!this.has(element)) {collection.push(element);return true;} else {return false;}};this.remove = function(element) {if(this.has(element)) {var i = collection.indexOf(element);collection.splice(i, 1);return true;}return false;};this.size = function() {return collection.length;};this.union = function(set) {var u = new Set();var c = this.values();var s = set.values();c.forEach(function(element){u.add(element);});s.forEach(function(element){u.add(element);});return u;};}
function Set() {
var collection = [];
this.has = function(element) {
return (collection.indexOf(element) !== -1);
};
this.values = function() {
return collection;
};
this.add = function(element) {
if(!this.has(element)){
collection.push(element);
return true;
}
return false;
};
this.remove = function(element) {
if(this.has(element)){
var index = collection.indexOf(element);
collection.splice(index,1);
return true;
}
return false;
};
this.size = function() {
return collection.length;
};
this.union = function(anotherSet){
const newSet = new Set();
const addToSet = el => newSet.add(el);
this.values().forEach(addToSet);
anotherSet.values().forEach(addToSet);
return newSet;
};
}
```
</section>