4d620dea1a
* chore(curriculum): update regex in use-braket-notation-* tests Update regex used in tests, so that tests are more forgiving and spaces tolerant. * Allow for spaces within brackets
69 lines
1.4 KiB
Markdown
69 lines
1.4 KiB
Markdown
---
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id: bd7123c9c450eddfaeb5bdef
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title: Use Bracket Notation to Find the Nth Character in a String
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challengeType: 1
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videoUrl: 'https://scrimba.com/c/cWPVJua'
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forumTopicId: 18343
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dashedName: use-bracket-notation-to-find-the-nth-character-in-a-string
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---
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# --description--
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You can also use <dfn>bracket notation</dfn> to get the character at other positions within a string.
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Remember that computers start counting at `0`, so the first character is actually the zeroth character.
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Example:
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```js
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const firstName = "Ada";
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const secondLetterOfFirstName = firstName[1];
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```
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`secondLetterOfFirstName` would have a value of the string `d`.
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# --instructions--
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Let's try to set `thirdLetterOfLastName` to equal the third letter of the `lastName` variable using bracket notation.
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**Hint:** Try looking at the example above if you get stuck.
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# --hints--
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The `thirdLetterOfLastName` variable should have the value of `v`.
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```js
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assert(thirdLetterOfLastName === 'v');
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```
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You should use bracket notation.
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```js
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assert(code.match(/thirdLetterOfLastName\s*=\s*lastName\s*\[\s*\d\s*\]/));
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```
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# --seed--
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## --after-user-code--
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```js
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(function(v){return v;})(thirdLetterOfLastName);
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```
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## --seed-contents--
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```js
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// Setup
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const lastName = "Lovelace";
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// Only change code below this line
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const thirdLetterOfLastName = lastName; // Change this line
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```
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# --solutions--
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```js
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const lastName = "Lovelace";
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const thirdLetterOfLastName = lastName[2];
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```
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