1.4 KiB
1.4 KiB
id, title, challengeType, forumTopicId, dashedName
id | title | challengeType | forumTopicId | dashedName |
---|---|---|---|---|
5900f4761000cf542c50ff88 | Problem 265: Binary Circles | 5 | 301914 | problem-265-binary-circles |
--description--
2^N
binary digits can be placed in a circle so that all the $N$-digit clockwise subsequences are distinct.
For N = 3
, two such circular arrangements are possible, ignoring rotations:

For the first arrangement, the 3-digit subsequences, in clockwise order, are: 000, 001, 010, 101, 011, 111, 110 and 100.
Each circular arrangement can be encoded as a number by concatenating the binary digits starting with the subsequence of all zeros as the most significant bits and proceeding clockwise. The two arrangements for N = 3
are thus represented as 23 and 29:
$${00010111}_2 = 23\\ {00011101}_2 = 29$$
Calling S(N)
the sum of the unique numeric representations, we can see that S(3) = 23 + 29 = 52
.
Find S(5)
.
--hints--
binaryCircles()
should return 209110240768
.
assert.strictEqual(binaryCircles(), 209110240768);
--seed--
--seed-contents--
function binaryCircles() {
return true;
}
binaryCircles();
--solutions--
// solution required