db369fbed1
* Removes comments in js challanges by default * fix local-scope-and-functions test regex * fix all languages * revert language changes * removed unnecessary removeJSComments from challenges * fix challanges in other languages * removed removeJSComments from all challanges
87 lines
1.6 KiB
Markdown
87 lines
1.6 KiB
Markdown
---
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id: 587d7b8b367417b2b2512b50
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title: Escribe funciones breves y declarativas con ES6
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challengeType: 1
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forumTopicId: 301224
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dashedName: write-concise-declarative-functions-with-es6
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---
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# --description--
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Al definir funciones dentro de objetos en ES5, tenemos que utilizar la palabra clave `function` de la siguiente manera:
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```js
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const person = {
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name: "Taylor",
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sayHello: function() {
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return `Hello! My name is ${this.name}.`;
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}
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};
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```
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Con ES6, puedes eliminar la palabra clave `function` y los dos puntos al definir funciones en objetos. Aquí hay un ejemplo de esta sintaxis:
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```js
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const person = {
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name: "Taylor",
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sayHello() {
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return `Hello! My name is ${this.name}.`;
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}
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};
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```
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# --instructions--
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Refactoriza la función `setGear` dentro del objeto `bicycle` para que utilice la sintaxis abreviada descrita arriba.
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# --hints--
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La expresión tradicional "function" no debe ser utilizada.
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```js
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(getUserInput) => assert(!code.match(/function/));
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```
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`setGear` debe ser una función declarativa.
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```js
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assert(
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typeof bicycle.setGear === 'function' && code.match(/setGear\s*\(.+\)\s*\{/)
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);
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```
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`bicycle.setGear(48)` debe cambiar el valor de `gear` a 48.
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```js
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assert(new bicycle.setGear(48).gear === 48);
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```
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# --seed--
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## --seed-contents--
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```js
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// Only change code below this line
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const bicycle = {
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gear: 2,
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setGear: function(newGear) {
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this.gear = newGear;
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}
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};
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// Only change code above this line
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bicycle.setGear(3);
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console.log(bicycle.gear);
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```
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# --solutions--
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```js
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const bicycle = {
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gear: 2,
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setGear(newGear) {
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this.gear = newGear;
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}
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};
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bicycle.setGear(3);
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```
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