Files
freeCodeCamp/curriculum/challenges/espanol/10-coding-interview-prep/project-euler/problem-46-goldbachs-other-conjecture.md
2021-02-07 14:08:31 +05:30

100 lines
2.0 KiB
Markdown
Raw Permalink Blame History

This file contains ambiguous Unicode characters

This file contains Unicode characters that might be confused with other characters. If you think that this is intentional, you can safely ignore this warning. Use the Escape button to reveal them.

---
id: 5900f39a1000cf542c50fead
title: 'Problem 46: Goldbach''s other conjecture'
challengeType: 5
forumTopicId: 302134
dashedName: problem-46-goldbachs-other-conjecture
---
# --description--
It was proposed by Christian Goldbach that every odd composite number can be written as the sum of a prime and twice a square.
<div style='margin-left: 2em;'>
9 = 7 + 2×1<sup>2</sup><br>
15 = 7 + 2×2<sup>2</sup><br>
21 = 3 + 2×3<sup>2</sup><br>
25 = 7 + 2×3<sup>2</sup><br>
27 = 19 + 2×2<sup>2</sup><br>
33 = 31 + 2×1<sup>2</sup>
</div>
It turns out that the conjecture was false.
What is the smallest odd composite that cannot be written as the sum of a prime and twice a square?
# --hints--
`goldbachsOtherConjecture()` should return a number.
```js
assert(typeof goldbachsOtherConjecture() === 'number');
```
`goldbachsOtherConjecture()` should return 5777.
```js
assert.strictEqual(goldbachsOtherConjecture(), 5777);
```
# --seed--
## --seed-contents--
```js
function goldbachsOtherConjecture() {
return true;
}
goldbachsOtherConjecture();
```
# --solutions--
```js
function goldbachsOtherConjecture() { function isPrime(num) {
if (num < 2) {
return false;
} else if (num === 2) {
return true;
}
const sqrtOfNum = Math.floor(num ** 0.5);
for (let i = 2; i <= sqrtOfNum + 1; i++) {
if (num % i === 0) {
return false;
}
}
return true;
}
function isSquare(num) {
return Math.sqrt(num) % 1 === 0;
}
// construct a list of prime numbers
const primes = [];
for (let i = 2; primes.length < 1000; i++) {
if (isPrime(i)) primes.push(i);
}
let num = 3;
let answer;
while (!answer) {
num += 2;
if (!isPrime(num)) {
let found = false;
for (let primeI = 0; primeI < primes.length && !found; primeI++) {
const square = (num - primes[primeI]) / 2;
if (isSquare(square)) {
found = true;
break;
}
}
if (!found) answer = num;
}
}
return answer;
}
```