Oliver Eyton-Williams ee1e8abd87
feat(curriculum): restore seed + solution to Chinese (#40683)
* feat(tools): add seed/solution restore script

* chore(curriculum): remove empty sections' markers

* chore(curriculum): add seed + solution to Chinese

* chore: remove old formatter

* fix: update getChallenges

parse translated challenges separately, without reference to the source

* chore(curriculum): add dashedName to English

* chore(curriculum): add dashedName to Chinese

* refactor: remove unused challenge property 'name'

* fix: relax dashedName requirement

* fix: stray tag

Remove stray `pre` tag from challenge file.

Signed-off-by: nhcarrigan <nhcarrigan@gmail.com>

Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
2021-01-12 19:31:00 -07:00

1.4 KiB

id, title, challengeType, forumTopicId, dashedName
id title challengeType forumTopicId dashedName
a5229172f011153519423690 Sum All Odd Fibonacci Numbers 5 16084 sum-all-odd-fibonacci-numbers

--description--

Given a positive integer num, return the sum of all odd Fibonacci numbers that are less than or equal to num.

The first two numbers in the Fibonacci sequence are 1 and 1. Every additional number in the sequence is the sum of the two previous numbers. The first six numbers of the Fibonacci sequence are 1, 1, 2, 3, 5 and 8.

For example, sumFibs(10) should return 10 because all odd Fibonacci numbers less than or equal to 10 are 1, 1, 3, and 5.

--hints--

sumFibs(1) should return a number.

assert(typeof sumFibs(1) === 'number');

sumFibs(1000) should return 1785.

assert(sumFibs(1000) === 1785);

sumFibs(4000000) should return 4613732.

assert(sumFibs(4000000) === 4613732);

sumFibs(4) should return 5.

assert(sumFibs(4) === 5);

sumFibs(75024) should return 60696.

assert(sumFibs(75024) === 60696);

sumFibs(75025) should return 135721.

assert(sumFibs(75025) === 135721);

--seed--

--seed-contents--

function sumFibs(num) {
  return num;
}

sumFibs(4);

--solutions--

function sumFibs(num) {
  var a = 1;
  var b = 1;
  var s = 0;
  while (a <= num) {
    if (a % 2 !== 0) {
      s += a;
    }
    a = [b, b=b+a][0];
  }
  return s;
}