Oliver Eyton-Williams 0bd52f8bd1

and change all the challenges to new `md` format.

2020-11-27 10:02:05 -08:00

1.7 KiB

Raw Blame History

id, title, challengeType, forumTopicId

id	title	challengeType	forumTopicId
ae9defd7acaf69703ab432ea	Smallest Common Multiple	5	16075

--description--

Find the smallest common multiple of the provided parameters that can be evenly divided by both, as well as by all sequential numbers in the range between these parameters.

The range will be an array of two numbers that will not necessarily be in numerical order.

For example, if given 1 and 3, find the smallest common multiple of both 1 and 3 that is also evenly divisible by all numbers between 1 and 3. The answer here would be 6.

--hints--

smallestCommons([1, 5]) should return a number.

assert.deepEqual(typeof smallestCommons([1, 5]), 'number');

smallestCommons([1, 5]) should return 60.

assert.deepEqual(smallestCommons([1, 5]), 60);

smallestCommons([5, 1]) should return 60.

assert.deepEqual(smallestCommons([5, 1]), 60);

smallestCommons([2, 10]) should return 2520.

assert.deepEqual(smallestCommons([2, 10]), 2520);

smallestCommons([1, 13]) should return 360360.

assert.deepEqual(smallestCommons([1, 13]), 360360);

smallestCommons([23, 18]) should return 6056820.

assert.deepEqual(smallestCommons([23, 18]), 6056820);

--seed--

--seed-contents--

function smallestCommons(arr) {
  return arr;
}


smallestCommons([1,5]);

--solutions--

function gcd(a, b) {
    while (b !== 0) {
        a = [b, b = a % b][0];
    }
    return a;
}

function lcm(a, b) {
    return (a * b) / gcd(a, b);
}

function smallestCommons(arr) {
  arr.sort(function(a,b) {return a-b;});
  var rng = [];
  for (var i = arr[0]; i <= arr[1]; i++) {
    rng.push(i);
  }
  return rng.reduce(lcm);
}

1.7 KiB Raw Blame History