* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
		
			
				
	
	
		
			137 lines
		
	
	
		
			3.0 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
			
		
		
	
	
			137 lines
		
	
	
		
			3.0 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
---
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id: 5cc0c1b32479e176caf3b422
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title: Check if Tree is Binary Search Tree
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challengeType: 1
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forumTopicId: 301624
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dashedName: check-if-tree-is-binary-search-tree
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---
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# --description--
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Since you already know what a binary search tree is, this challenge will establish how it is you can tell that a tree is a binary search tree or not.
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The main distinction of a binary search tree is that the nodes are ordered in an organized fashion. Nodes have at most 2 child nodes (placed to the right and/or left) based on if the child node's value is greater than or equal to (right) or less than (left) the parent node.
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# --instructions--
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In this challenge, you will create a utility for your tree. Write a JavaScript method `isBinarySearchTree` which takes a tree as an input and returns a boolean value for whether the tree is a binary search tree or not. Use recursion whenever possible.
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# --hints--
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Your Binary Search Tree should return true when checked with `isBinarySearchTree()`.
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```js
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assert(
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  (function () {
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    var test = false;
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    if (typeof BinarySearchTree !== 'undefined') {
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      test = new BinarySearchTree();
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    } else {
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      return false;
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    }
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    test.push(1);
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    test.push(5);
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    test.push(3);
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    test.push(2);
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    test.push(4);
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    return isBinarySearchTree(test) == true;
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  })()
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);
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```
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# --seed--
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## --after-user-code--
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```js
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BinarySearchTree.prototype.push = function(val) {
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  var root = this.root;
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  if (!root) {
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    this.root = new Node(val);
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    return;
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  }
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  var currentNode = root;
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  var newNode = new Node(val);
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  while (currentNode) {
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    if (val < currentNode.value) {
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      if (!currentNode.left) {
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        currentNode.left = newNode;
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        break;
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      } else {
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        currentNode = currentNode.left;
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      }
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    } else {
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      if (!currentNode.right) {
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        currentNode.right = newNode;
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        break;
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      } else {
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        currentNode = currentNode.right;
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      }
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    }
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  }
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};
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```
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## --seed-contents--
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```js
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var displayTree = (tree) => console.log(JSON.stringify(tree, null, 2));
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function Node(value) {
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  this.value = value;
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  this.left = null;
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  this.right = null;
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}
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function BinarySearchTree() {
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  this.root = null;
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}
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function isBinarySearchTree(tree) {
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  // Only change code below this line
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  // Only change code above this line
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}
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```
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# --solutions--
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```js
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var displayTree = (tree) => console.log(JSON.stringify(tree, null, 2));
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function Node(value) {
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  this.value = value;
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  this.left = null;
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  this.right = null;
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}
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function BinarySearchTree() {
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  this.root = null;
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}
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function isBinarySearchTree(tree) {
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  if (tree.root == null) {
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    return null;
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  } else {
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    let isBST = true;
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    function checkTree(node) {
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      if (node.left != null) {
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        const left = node.left;
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        if (left.value > node.value) {
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          isBST = false;
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        } else {
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          checkTree(left);
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        }
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      }
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      if (node.right != null) {
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        const right = node.right;
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        if (right.value < node.value) {
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          isBST = false;
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        } else {
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          checkTree(right);
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        }
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      }
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    }
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    checkTree(tree.root);
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    return isBST;
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  }
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};
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```
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