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Co-Authored-By: Tom <20648924+moT01@users.noreply.github.com>

* fix: add extra line

Co-Authored-By: Tom <20648924+moT01@users.noreply.github.com>

* fix: add extra line

Co-Authored-By: Tom <20648924+moT01@users.noreply.github.com>

* fix: add extra line

Co-Authored-By: Tom <20648924+moT01@users.noreply.github.com>

* fix: add extra line

Co-Authored-By: Tom <20648924+moT01@users.noreply.github.com>

* fix: add extra line

Co-Authored-By: Tom <20648924+moT01@users.noreply.github.com>

* fix: add extra line

Co-Authored-By: Tom <20648924+moT01@users.noreply.github.com>

* fix: add extra line

Co-Authored-By: Tom <20648924+moT01@users.noreply.github.com>

* fix: add extra line

Co-Authored-By: Tom <20648924+moT01@users.noreply.github.com>
2019-07-01 08:49:24 -05:00

847 B

title
title
Special Pythagorean triplet

Problem 9: Special Pythagorean triplet

Method:

  • In this challenge we need to find the pythagorean triple.
  • We have the following information - a < b < c
  • Based on this, we can make a loop starting from a = 0 and b = a since a < b always.
  • We also know that a + b + c = n and a^2 + b^2 = c^2, since we have a, b and n. We can find c and see if it satisfies the triplet theorem.

Solution:

function specialPythagoreanTriplet(n) {
  let sumOfabc = n;
  for (let a = 1; a < n; a++){
    for (let b = a; b < n; b++){
      let c = n - a- b;
      if (c > 0){
        if (c**2 == a**2 + b**2){
          return a*b*c;
        }
      }
    }
  } 
}

specialPythagoreanTriplet(1000);

References: