2020-09-29 22:09:04 +02:00

1.3 KiB

id, challengeType, title, forumTopicId
id challengeType title forumTopicId
5900f4931000cf542c50ffa4 5 Problem 293: Pseudo-Fortunate Numbers 301945

Description

An even positive integer N will be called admissible, if it is a power of 2 or its distinct prime factors are consecutive primes. The first twelve admissible numbers are 2,4,6,8,12,16,18,24,30,32,36,48.

If N is admissible, the smallest integer M > 1 such that N+M is prime, will be called the pseudo-Fortunate number for N.

For example, N=630 is admissible since it is even and its distinct prime factors are the consecutive primes 2,3,5 and 7. The next prime number after 631 is 641; hence, the pseudo-Fortunate number for 630 is M=11. It can also be seen that the pseudo-Fortunate number for 16 is 3.

Find the sum of all distinct pseudo-Fortunate numbers for admissible numbers N less than 109.

Instructions

Tests

tests:
  - text: <code>euler293()</code> should return 2209.
    testString: assert.strictEqual(euler293(), 2209);

Challenge Seed

function euler293() {

  return true;
}

euler293();

Solution

// solution required