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freeCodeCamp/curriculum/challenges/chinese/10-coding-interview-prep/rosetta-code/element-wise-operations.md
Oliver Eyton-Williams ee1e8abd87 feat(curriculum): restore seed + solution to Chinese (#40683)
* feat(tools): add seed/solution restore script

* chore(curriculum): remove empty sections' markers

* chore(curriculum): add seed + solution to Chinese

* chore: remove old formatter

* fix: update getChallenges

parse translated challenges separately, without reference to the source

* chore(curriculum): add dashedName to English

* chore(curriculum): add dashedName to Chinese

* refactor: remove unused challenge property 'name'

* fix: relax dashedName requirement

* fix: stray tag

Remove stray `pre` tag from challenge file.

Signed-off-by: nhcarrigan <nhcarrigan@gmail.com>

Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
2021-01-12 19:31:00 -07:00

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---
id: 599c333915e0ea32d04d4bec
title: 元素操作
challengeType: 5
videoUrl: ''
dashedName: element-wise-operations
---
# --description--
<p>实现基本的元素矩阵 - 矩阵和标量矩阵运算。 </p><p>实行: </p><p> :: *另外</p><p> :: *减法</p><p> :: *乘法</p><p> :: *分裂</p><p> :: *取幂</p><p>第一个参数是要执行的操作例如用于矩阵加法的“m_add”和用于标量加法的“s_add”。第二和第三参数将是要在其上执行操作的矩阵。 </p>
# --hints--
`operation`是一种功能。
```js
assert(typeof operation === 'function');
```
`operation("m_add",[[1,2],[3,4]],[[1,2],[3,4]])`应返回`[[2,4],[6,8]]`
```js
assert.deepEqual(
operation(
'm_add',
[
[1, 2],
[3, 4]
],
[
[1, 2],
[3, 4]
]
),
[
[2, 4],
[6, 8]
]
);
```
`operation("s_add",[[1,2],[3,4]],[[1,2],[3,4]])`应返回`[[3,4],[5,6]]`
```js
assert.deepEqual(
operation(
's_add',
[
[1, 2],
[3, 4]
],
2
),
[
[3, 4],
[5, 6]
]
);
```
`operation("m_sub",[[1,2],[3,4]],[[1,2],[3,4]])`应返回`[[0,0],[0,0]]`
```js
assert.deepEqual(
operation(
'm_sub',
[
[1, 2],
[3, 4]
],
[
[1, 2],
[3, 4]
]
),
[
[0, 0],
[0, 0]
]
);
```
`operation("m_mult",[[1,2],[3,4]],[[1,2],[3,4]])`应该返回`[[1,4],[9,16]]`
```js
assert.deepEqual(
operation(
'm_mult',
[
[1, 2],
[3, 4]
],
[
[1, 2],
[3, 4]
]
),
[
[1, 4],
[9, 16]
]
);
```
`operation("m_div",[[1,2],[3,4]],[[1,2],[3,4]])`应返回`[[1,1],[1,1]]`
```js
assert.deepEqual(
operation(
'm_div',
[
[1, 2],
[3, 4]
],
[
[1, 2],
[3, 4]
]
),
[
[1, 1],
[1, 1]
]
);
```
`operation("m_exp",[[1,2],[3,4]],[[1,2],[3,4]])`应返回`[[1,4],[27,256]]`
```js
assert.deepEqual(
operation(
'm_exp',
[
[1, 2],
[3, 4]
],
[
[1, 2],
[3, 4]
]
),
[
[1, 4],
[27, 256]
]
);
```
`operation("m_add",[[1,2,3,4],[5,6,7,8]],[[9,10,11,12],[13,14,15,16]])`应该返回`[[10,12,14,16],[18,20,22,24]]`
```js
assert.deepEqual(
operation(
'm_add',
[
[1, 2, 3, 4],
[5, 6, 7, 8]
],
[
[9, 10, 11, 12],
[13, 14, 15, 16]
]
),
[
[10, 12, 14, 16],
[18, 20, 22, 24]
]
);
```
# --seed--
## --seed-contents--
```js
function operation(op, arr1, arr2) {
}
```
# --solutions--
```js
function operation(op, arr1, arr2) {
const ops = {
add: ((a, b) => a + b),
sub: ((a, b) => a - b),
mult: ((a, b) => a * b),
div: ((a, b) => a / b),
exp: ((a, b) => Math.pow(a, b))
};
const ifm = op.startsWith('m');
const doOp = ops[op.substring(2)];
for (let i = 0; i < arr1.length; i++) {
for (let j = 0; j < arr1[0].length; j++) {
arr1[i][j] = doOp(arr1[i][j], (ifm) ? (arr2[i][j]) : (arr2));
}
}
return arr1;
}
```