2.4 KiB
2.4 KiB
id, title, challengeType, forumTopicId
id | title | challengeType | forumTopicId |
---|---|---|---|
587d7dae367417b2b2512b7b | Understand Own Properties | 1 | 301326 |
Description
Bird
constructor defines two properties: name
and numLegs
:
function Bird(name) {
this.name = name;
this.numLegs = 2;
}
let duck = new Bird("Donald");
let canary = new Bird("Tweety");
name
and numLegs
are called own
properties, because they are defined directly on the instance object. That means that duck
and canary
each has its own separate copy of these properties.
In fact every instance of Bird
will have its own copy of these properties.
The following code adds all of the own
properties of duck
to the array ownProps
:
let ownProps = [];
for (let property in duck) {
if(duck.hasOwnProperty(property)) {
ownProps.push(property);
}
}
console.log(ownProps); // prints [ "name", "numLegs" ]
Instructions
own
properties of canary
to the array ownProps
.
Tests
tests:
- text: <code>ownProps</code> should include the values <code>"numLegs"</code> and <code>"name"</code>.
testString: assert(ownProps.indexOf('name') !== -1 && ownProps.indexOf('numLegs') !== -1);
- text: You should solve this challenge without using the built in method <code>Object.keys()</code>.
testString: assert(!/Object(\.keys|\[(['"`])keys\2\])/.test(code));
- text: You should solve this challenge without hardcoding the <code>ownProps</code> array.
testString: assert(!/\[\s*(?:'|")(?:name|numLegs)|(?:push|concat)\(\s*(?:'|")(?:name|numLegs)/.test(code));
Challenge Seed
function Bird(name) {
this.name = name;
this.numLegs = 2;
}
let canary = new Bird("Tweety");
let ownProps = [];
// Add your code below this line
Solution
function Bird(name) {
this.name = name;
this.numLegs = 2;
}
let canary = new Bird("Tweety");
function getOwnProps (obj) {
const props = [];
for (let prop in obj) {
if (obj.hasOwnProperty(prop)) {
props.push(prop);
}
}
return props;
}
const ownProps = getOwnProps(canary);