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freeCodeCamp/curriculum/challenges/chinese/02-javascript-algorithms-and-data-structures/basic-javascript/introducing-else-if-statements.chinese.md
Kristofer Koishigawa b3213fc892 fix(i18n): chinese test suite (#38220) 
* fix: Chinese test suite

Add localeTiltes, descriptions, and adjust test text and testStrings to get the automated test suite working.

* fix: ran script, updated testStrings and solutions
2020-03-03 18:49:47 +05:30

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id, title, challengeType, videoUrl, localeTitle
id title challengeType videoUrl localeTitle
56533eb9ac21ba0edf2244db Introducing Else If Statements 1 如果声明引入Else

Description

如果您有多个需要解决的条件，可以将if语句与else if语句链接在一起。
if（num> 15）{
返回“大于15”;
} else if（num <5）{
返回“小于5”;
} else {
返回“5到15之间”;
}

Instructions

转换逻辑以使用else if语句。

Tests

tests:
  - text: 你应该至少有两个<code>else</code>语句
    testString: assert(code.match(/else/g).length > 1);
  - text: 你应该至少有两个<code>if</code>语句
    testString: assert(code.match(/if/g).length > 1);
  - text: 您应该为每个条件关闭并打开花括号
    testString: assert(code.match(/if\s*\((.+)\)\s*\{[\s\S]+\}\s*else if\s*\((.+)\)\s*\{[\s\S]+\}\s*else\s*\{[\s\S]+\s*\}/));
  - text: <code>testElseIf(0)</code>应返回“小于5”
    testString: assert(testElseIf(0) === "Smaller than 5");
  - text: <code>testElseIf(5)</code>应该返回“5到10之间”
    testString: assert(testElseIf(5) === "Between 5 and 10");
  - text: <code>testElseIf(7)</code>应返回“5到10之间”
    testString: assert(testElseIf(7) === "Between 5 and 10");
  - text: <code>testElseIf(10)</code>应返回“5到10之间”
    testString: assert(testElseIf(10) === "Between 5 and 10");
  - text: <code>testElseIf(12)</code>应返回“大于10”
    testString: assert(testElseIf(12) === "Greater than 10");

Challenge Seed

function testElseIf(val) {
  if (val > 10) {
    return "Greater than 10";
  }

  if (val < 5) {
    return "Smaller than 5";
  }

  return "Between 5 and 10";
}

// Change this value to test
testElseIf(7);

Solution

// solution required