97 lines
		
	
	
		
			1.8 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
			
		
		
	
	
			97 lines
		
	
	
		
			1.8 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
| ---
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| id: 599d15309e88c813a40baf58
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| title: Entropy
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| challengeType: 5
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| forumTopicId: 302254
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| dashedName: entropy
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| ---
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| 
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| # --description--
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| 
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| Calculate the Shannon entropy H of a given input string.
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| 
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| Given the discreet random variable $X$ that is a string of $N$ "symbols" (total characters) consisting of $n$ different characters (n=2 for binary), the Shannon entropy of X in bits/symbol is:
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| 
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| $H_2(X) = -\\sum\_{i=1}^n \\frac{count_i}{N} \\log_2 \\left(\\frac{count_i}{N}\\right)$
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| 
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| where $count_i$ is the count of character $n_i$.
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| 
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| # --hints--
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| 
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| `entropy` should be a function.
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| 
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| ```js
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| assert(typeof entropy === 'function');
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| ```
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| 
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| `entropy("0")` should return `0`
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| 
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| ```js
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| assert.equal(entropy('0'), 0);
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| ```
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| 
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| `entropy("01")` should return `1`
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| 
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| ```js
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| assert.equal(entropy('01'), 1);
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| ```
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| 
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| `entropy("0123")` should return `2`
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| 
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| ```js
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| assert.equal(entropy('0123'), 2);
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| ```
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| 
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| `entropy("01234567")` should return `3`
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| 
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| ```js
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| assert.equal(entropy('01234567'), 3);
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| ```
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| 
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| `entropy("0123456789abcdef")` should return `4`
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| 
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| ```js
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| assert.equal(entropy('0123456789abcdef'), 4);
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| ```
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| 
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| `entropy("1223334444")` should return `1.8464393446710154`
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| 
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| ```js
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| assert.equal(entropy('1223334444'), 1.8464393446710154);
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| ```
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| 
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| # --seed--
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| 
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| ## --seed-contents--
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| 
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| ```js
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| function entropy(s) {
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| 
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| }
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| ```
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| 
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| # --solutions--
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| 
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| ```js
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| function entropy(s) {
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|     // Create a dictionary of character frequencies and iterate over it.
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|   function process(s, evaluator) {
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|     let h = Object.create(null),
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|       k;
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|     s.split('').forEach(c => {
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|       h[c] && h[c]++ || (h[c] = 1); });
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|     if (evaluator) for (k in h) evaluator(k, h[k]);
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|     return h;
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|   }
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|     // Measure the entropy of a string in bits per symbol.
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| 
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|   let sum = 0,
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|     len = s.length;
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|   process(s, (k, f) => {
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|     const p = f / len;
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|     sum -= p * Math.log(p) / Math.log(2);
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|   });
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|   return sum;
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| }
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| ```
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