freeCodeCamp/sum-all-numbers-in-a-range.english.md at 203c9823e8f35ada1ecf35ac20444ac7ff510401

Mo Zargham 437ba8b103 fix(curriculum): Read-search-ask link now point to correct url as noted in the issue (#37753 )

* fix: broken Read-search-ask link now point to correct url

* fix: changed link to original forum link with more views

* fix: changed http links to correct version

* fix: link in help modal

2019-11-19 19:54:48 -05:00

1.7 KiB

Raw Blame History

id, title, isRequired, challengeType, forumTopicId

id	title	isRequired	challengeType	forumTopicId
a3566b1109230028080c9345	Sum All Numbers in a Range	true	5	16083

Description

We'll pass you an array of two numbers. Return the sum of those two numbers plus the sum of all the numbers between them. The lowest number will not always come first.

For example, sumAll([4,1]) should return 10 because sum of all the numbers between 1 and 4 (both inclusive) is 10.

Remember to use Read-Search-Ask if you get stuck. Try to pair program. Write your own code.

Instructions

Tests

tests:
  - text: <code>sumAll([1, 4])</code> should return a number.
    testString: assert(typeof sumAll([1, 4]) === 'number');
  - text: <code>sumAll([1, 4])</code> should return 10.
    testString: assert.deepEqual(sumAll([1, 4]), 10);
  - text: <code>sumAll([4, 1])</code> should return 10.
    testString: assert.deepEqual(sumAll([4, 1]), 10);
  - text: <code>sumAll([5, 10])</code> should return 45.
    testString: assert.deepEqual(sumAll([5, 10]), 45);
  - text: <code>sumAll([10, 5])</code> should return 45.
    testString: assert.deepEqual(sumAll([10, 5]), 45);

Challenge Seed

function sumAll(arr) {
  return 1;
}

sumAll([1, 4]);

Solution

function sumAll(arr) {
  var sum = 0;
  arr.sort(function(a,b) {return a-b;});
  for (var i = arr[0]; i <= arr[1]; i++) {
    sum += i;
  }
  return sum;
}

1.7 KiB Raw Blame History