* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
		
			
				
	
	
		
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			6.3 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
			
		
		
	
	
			262 lines
		
	
	
		
			6.3 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
| ---
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| id: 587d8258367417b2b2512c7f
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| title: Use Breadth First Search in a Binary Search Tree
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| challengeType: 1
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| forumTopicId: 301718
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| dashedName: use-breadth-first-search-in-a-binary-search-tree
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| ---
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| 
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| # --description--
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| 
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| Here we will introduce another tree traversal method: breadth-first search. In contrast to the depth-first search methods from the last challenge, breadth-first search explores all the nodes in a given level within a tree before continuing on to the next level. Typically, queues are utilized as helper data structures in the design of breadth-first search algorithms.
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| 
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| In this method, we start by adding the root node to a queue. Then we begin a loop where we dequeue the first item in the queue, add it to a new array, and then inspect both its child subtrees. If its children are not null, they are each enqueued. This process continues until the queue is empty.
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| 
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| # --instructions--
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| 
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| Let's create a breadth-first search method in our tree called `levelOrder`. This method should return an array containing the values of all the tree nodes, explored in a breadth-first manner. Be sure to return the values in the array, not the nodes themselves. A level should be traversed from left to right. Next, let's write a similar method called `reverseLevelOrder` which performs the same search but in the reverse direction (right to left) at each level.
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| 
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| # --hints--
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| 
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| The `BinarySearchTree` data structure should exist.
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| 
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| ```js
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| assert(
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|   (function () {
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|     var test = false;
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|     if (typeof BinarySearchTree !== 'undefined') {
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|       test = new BinarySearchTree();
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|     }
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|     return typeof test == 'object';
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|   })()
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| );
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| ```
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| 
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| The binary search tree should have a method called `levelOrder`.
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| 
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| ```js
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| assert(
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|   (function () {
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|     var test = false;
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|     if (typeof BinarySearchTree !== 'undefined') {
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|       test = new BinarySearchTree();
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|     } else {
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|       return false;
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|     }
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|     return typeof test.levelOrder == 'function';
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|   })()
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| );
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| ```
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| 
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| The binary search tree should have a method called `reverseLevelOrder`.
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| 
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| ```js
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| assert(
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|   (function () {
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|     var test = false;
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|     if (typeof BinarySearchTree !== 'undefined') {
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|       test = new BinarySearchTree();
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|     } else {
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|       return false;
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|     }
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|     return typeof test.reverseLevelOrder == 'function';
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|   })()
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| );
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| ```
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| 
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| The `levelOrder` method should return an array of the tree node values explored in level order.
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| 
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| ```js
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| assert(
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|   (function () {
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|     var test = false;
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|     if (typeof BinarySearchTree !== 'undefined') {
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|       test = new BinarySearchTree();
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|     } else {
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|       return false;
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|     }
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|     if (typeof test.levelOrder !== 'function') {
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|       return false;
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|     }
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|     test.add(7);
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|     test.add(1);
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|     test.add(9);
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|     test.add(0);
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|     test.add(3);
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|     test.add(8);
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|     test.add(10);
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|     test.add(2);
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|     test.add(5);
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|     test.add(4);
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|     test.add(6);
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|     return test.levelOrder().join('') == '719038102546';
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|   })()
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| );
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| ```
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| 
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| The `reverseLevelOrder` method should return an array of the tree node values explored in reverse level order.
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| 
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| ```js
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| assert(
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|   (function () {
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|     var test = false;
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|     if (typeof BinarySearchTree !== 'undefined') {
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|       test = new BinarySearchTree();
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|     } else {
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|       return false;
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|     }
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|     if (typeof test.reverseLevelOrder !== 'function') {
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|       return false;
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|     }
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|     test.add(7);
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|     test.add(1);
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|     test.add(9);
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|     test.add(0);
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|     test.add(3);
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|     test.add(8);
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|     test.add(10);
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|     test.add(2);
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|     test.add(5);
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|     test.add(4);
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|     test.add(6);
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|     return test.reverseLevelOrder().join('') == '791108305264';
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|   })()
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| );
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| ```
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| 
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| The `levelOrder` method should return `null` for an empty tree.
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| 
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| ```js
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| assert(
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|   (function () {
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|     var test = false;
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|     if (typeof BinarySearchTree !== 'undefined') {
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|       test = new BinarySearchTree();
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|     } else {
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|       return false;
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|     }
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|     if (typeof test.levelOrder !== 'function') {
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|       return false;
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|     }
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|     return test.levelOrder() == null;
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|   })()
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| );
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| ```
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| 
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| The `reverseLevelOrder` method should return `null` for an empty tree.
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| 
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| ```js
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| assert(
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|   (function () {
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|     var test = false;
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|     if (typeof BinarySearchTree !== 'undefined') {
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|       test = new BinarySearchTree();
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|     } else {
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|       return false;
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|     }
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|     if (typeof test.reverseLevelOrder !== 'function') {
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|       return false;
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|     }
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|     return test.reverseLevelOrder() == null;
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|   })()
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| );
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| ```
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| 
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| # --seed--
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| 
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| ## --after-user-code--
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| 
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| ```js
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| BinarySearchTree.prototype = Object.assign(
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|   BinarySearchTree.prototype,
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|   {
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|     add: function(value) {
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|       function searchTree(node) {
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|         if (value < node.value) {
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|           if (node.left == null) {
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|             node.left = new Node(value);
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|             return;
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|           } else if (node.left != null) {
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|             return searchTree(node.left);
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|           }
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|         } else if (value > node.value) {
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|           if (node.right == null) {
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|             node.right = new Node(value);
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|             return;
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|           } else if (node.right != null) {
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|             return searchTree(node.right);
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|           }
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|         } else {
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|           return null;
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|         }
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|       }
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|       var node = this.root;
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|       if (node == null) {
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|         this.root = new Node(value);
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|         return;
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|       } else {
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|         return searchTree(node);
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|       }
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|     }
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|   }
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| );
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| ```
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| 
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| ## --seed-contents--
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| 
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| ```js
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| var displayTree = tree => console.log(JSON.stringify(tree, null, 2));
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| function Node(value) {
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|   this.value = value;
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|   this.left = null;
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|   this.right = null;
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| }
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| function BinarySearchTree() {
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|   this.root = null;
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|   // Only change code below this line
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|   
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|   // Only change code above this line
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| }
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| ```
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| 
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| # --solutions--
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| 
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| ```js
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| var displayTree = tree => console.log(JSON.stringify(tree, null, 2));
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| function Node(value) {
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|   this.value = value;
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|   this.left = null;
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|   this.right = null;
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| }
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| function BinarySearchTree() {
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|   this.root = null;
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|   // Only change code below this line
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|   this.levelOrder = (root = this.root) => {
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|     if(!root) return null;
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|     let queue = [root];
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|     let results = [];
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|     while(queue.length > 0) {
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|       let node = queue.shift();
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|       results.push(node.value);
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|       if(node.left) queue.push(node.left);
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|       if(node.right) queue.push(node.right);
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|     }
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|     return results;
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|   }
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| 
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|   this.reverseLevelOrder = (root = this.root) => {
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|     if(!root) return null;
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|     let queue = [root];
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|     let results = [] ;
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|     while ( queue.length > 0) {
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|       let node = queue.shift();
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|       results.push(node.value);
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|       if(node.right) queue.push(node.right);
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|       if(node.left ) queue.push(node.left);
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|     }
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|     return results;
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|   }
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|   // Only change code above this line
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| }
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| ```
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