* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
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1.8 KiB
id, title, challengeType, forumTopicId, dashedName
| id | title | challengeType | forumTopicId | dashedName |
|---|---|---|---|---|
| 5900f5191000cf542c51002b | Problem 428: Necklace of Circles | 5 | 302098 | problem-428-necklace-of-circles |
--description--
Let a, b and c be positive numbers.
Let W, X, Y, Z be four collinear points where |WX| = a, |XY| = b, |YZ| = c and |WZ| = a + b + c.
Let Cin be the circle having the diameter XY.
Let Cout be the circle having the diameter WZ.
The triplet (a, b, c) is called a necklace triplet if you can place k ≥ 3 distinct circles C1, C2, ..., Ck such that:
- Ci has no common interior points with any Cj for 1 ≤ i, j ≤ k and i ≠ j,
- Ci is tangent to both Cin and Cout for 1 ≤ i ≤ k,
- Ci is tangent to Ci+1 for 1 ≤ i < k, and
- Ck is tangent to C1.
Let T(n) be the number of necklace triplets (a, b, c) such that a, b and c are positive integers, and b ≤ n. For example, T(1) = 9, T(20) = 732 and T(3000) = 438106.
Find T(1 000 000 000).
--hints--
necklace(1000000000) should return 747215561862.
assert.strictEqual(necklace(1000000000), 747215561862);
--seed--
--seed-contents--
function necklace(n) {
return true;
}
necklace(1000000000)
--solutions--
// solution required