ee1e8abd87
* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
100 lines
1.7 KiB
Markdown
100 lines
1.7 KiB
Markdown
---
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id: 5a23c84252665b21eecc7e7a
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title: 生成小写ASCII字母表
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challengeType: 5
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videoUrl: ''
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dashedName: generate-lower-case-ascii-alphabet
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---
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# --description--
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编写一个函数以生成给定范围的小写ASCII字符数组。例如：对于范围1到4，函数应返回`['a','b','c','d']` 。
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# --hints--
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`lascii`应该是一个功能。
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```js
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assert(typeof lascii == 'function');
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```
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`lascii("a","d")`应该返回一个数组。
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```js
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assert(Array.isArray(lascii('a', 'd')));
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```
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`lascii("a","d")`应该返回`[ "a", "b", "c", "d" ]` 。
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```js
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assert.deepEqual(lascii('a', 'd'), results[0]);
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```
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`lascii("c","i")`应该返回`[ "c", "d", "e", "f", "g", "h", "i" ]` 。
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```js
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assert.deepEqual(lascii('c', 'i'), results[1]);
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```
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`lascii("m","q")`应该返回`[ "m", "n", "o", "p", "q" ]` 。
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```js
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assert.deepEqual(lascii('m', 'q'), results[2]);
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```
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`lascii("k","n")`应返回`[ "k", "l", "m", "n" ]` 。
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```js
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assert.deepEqual(lascii('k', 'n'), results[3]);
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```
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`lascii("t","z")`应该返回`[ "t", "u", "v", "w", "x", "y", "z" ]` 。
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```js
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assert.deepEqual(lascii('t', 'z'), results[4]);
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```
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# --seed--
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## --after-user-code--
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```js
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let results=[
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[ 'a', 'b', 'c', 'd' ],
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[ 'c', 'd', 'e', 'f', 'g', 'h', 'i' ],
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[ 'm', 'n', 'o', 'p', 'q' ],
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[ 'k', 'l', 'm', 'n' ],
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[ 't', 'u', 'v', 'w', 'x', 'y', 'z' ]
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]
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```
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## --seed-contents--
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```js
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function lascii(cFrom, cTo) {
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}
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```
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# --solutions--
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```js
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function lascii(cFrom, cTo) {
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function cRange(cFrom, cTo) {
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var iStart = cFrom.charCodeAt(0);
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return Array.apply(
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null, Array(cTo.charCodeAt(0) - iStart + 1)
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).map(function (_, i) {
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return String.fromCharCode(iStart + i);
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});
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}
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return cRange(cFrom, cTo);
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}
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```
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