freeCodeCamp/curriculum/challenges/russian/02-javascript-algorithms-and-data-structures/basic-javascript/compound-assignment-with-augmented-subtraction.russian.md

id, title, challengeType, videoUrl, forumTopicId, localeTitle

id	title	challengeType	videoUrl	forumTopicId	localeTitle
56533eb9ac21ba0edf2244b0	Compound Assignment With Augmented Subtraction	1	https://scrimba.com/c/c2Qv7AV	16660	Соединение с расширенной вычитанием

Description

Как и оператор += , -= вычитает число из переменной. myVar = myVar - 5; вычитает 5 из myVar . Это можно переписать как: myVar -= 5;

Instructions

Преобразуйте присвоения для a , b и c для использования оператора -= .

Tests

tests:
  - text: <code>a</code> should equal <code>5</code>
    testString: assert(a === 5);
  - text: <code>b</code> should equal <code>-6</code>
    testString: assert(b === -6);
  - text: <code>c</code> should equal <code>2</code>
    testString: assert(c === 2);
  - text: You should use the <code>-=</code> operator for each variable
    testString: assert(code.match(/-=/g).length === 3);
  - text: Do not modify the code above the line
    testString: assert(/var a = 11;/.test(code) && /var b = 9;/.test(code) && /var c = 3;/.test(code));

Challenge Seed

var a = 11;
var b = 9;
var c = 3;

// Only modify code below this line

a = a - 6;
b = b - 15;
c = c - 1;

After Tests

(function(a,b,c){ return "a = " + a + ", b = " + b + ", c = " + c; })(a,b,c);

Solution

var a = 11;
var b = 9;
var c = 3;

a -= 6;
b -= 15;
c -= 1;