ee1e8abd87
* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
92 lines
1.3 KiB
Markdown
92 lines
1.3 KiB
Markdown
---
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id: 56533eb9ac21ba0edf2244b2
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title: Compound Assignment With Augmented Division
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challengeType: 1
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videoUrl: 'https://scrimba.com/c/c2QvKT2'
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forumTopicId: 16659
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dashedName: compound-assignment-with-augmented-division
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---
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# --description--
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The `/=` operator divides a variable by another number.
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`myVar = myVar / 5;`
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Will divide `myVar` by `5`. This can be rewritten as:
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`myVar /= 5;`
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# --instructions--
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Convert the assignments for `a`, `b`, and `c` to use the `/=` operator.
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# --hints--
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`a` should equal `4`.
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```js
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assert(a === 4);
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```
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`b` should equal `27`.
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```js
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assert(b === 27);
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```
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`c` should equal `3`.
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```js
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assert(c === 3);
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```
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You should use the `/=` operator for each variable.
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```js
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assert(code.match(/\/=/g).length === 3);
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```
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You should not modify the code above the specified comment.
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```js
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assert(
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/var a = 48;/.test(code) &&
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/var b = 108;/.test(code) &&
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/var c = 33;/.test(code)
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);
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```
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# --seed--
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## --after-user-code--
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```js
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(function(a,b,c){ return "a = " + a + ", b = " + b + ", c = " + c; })(a,b,c);
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```
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## --seed-contents--
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```js
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var a = 48;
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var b = 108;
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var c = 33;
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// Only change code below this line
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a = a / 12;
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b = b / 4;
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c = c / 11;
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```
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# --solutions--
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```js
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var a = 48;
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var b = 108;
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var c = 33;
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a /= 12;
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b /= 4;
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c /= 11;
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```
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