4.0 KiB

id, title, challengeType, forumTopicId
id title challengeType forumTopicId
a5de63ebea8dbee56860f4f2 数组的对称差 5 16008

--description--

在这道题目中,我们需要实现一个函数,它可以比较两个输入数组并返回一个新数组;返回的新数组需包含传入的两个数组中,仅在一个数组里出现的元素。如果某个元素同时出现在两个数组中,则不应包含在返回的数组里。换言之,我们需要返回两个数组的对称差。

注意:
返回数组中的元素顺序不会影响挑战是否通过。

--hints--

diffArray([1, 2, 3, 5], [1, 2, 3, 4, 5]) 应返回一个数组。

assert(typeof diffArray([1, 2, 3, 5], [1, 2, 3, 4, 5]) === 'object');

["diorite", "andesite", "grass", "dirt", "pink wool", "dead shrub"], ["diorite", "andesite", "grass", "dirt", "dead shrub"] 应返回 ["pink wool"]

assert.sameMembers(
  diffArray(
    ['diorite', 'andesite', 'grass', 'dirt', 'pink wool', 'dead shrub'],
    ['diorite', 'andesite', 'grass', 'dirt', 'dead shrub']
  ),
  ['pink wool']
);

["diorite", "andesite", "grass", "dirt", "pink wool", "dead shrub"], ["diorite", "andesite", "grass", "dirt", "dead shrub"] 应返回一个长度为 1 的数组。

assert(
  diffArray(
    ['diorite', 'andesite', 'grass', 'dirt', 'pink wool', 'dead shrub'],
    ['diorite', 'andesite', 'grass', 'dirt', 'dead shrub']
  ).length === 1
);

["andesite", "grass", "dirt", "pink wool", "dead shrub"], ["diorite", "andesite", "grass", "dirt", "dead shrub"] 应返回 ["diorite", "pink wool"]

assert.sameMembers(
  diffArray(
    ['andesite', 'grass', 'dirt', 'pink wool', 'dead shrub'],
    ['diorite', 'andesite', 'grass', 'dirt', 'dead shrub']
  ),
  ['diorite', 'pink wool']
);

["andesite", "grass", "dirt", "pink wool", "dead shrub"], ["diorite", "andesite", "grass", "dirt", "dead shrub"] 应返回一个长度为 2 的数组。

assert(
  diffArray(
    ['andesite', 'grass', 'dirt', 'pink wool', 'dead shrub'],
    ['diorite', 'andesite', 'grass', 'dirt', 'dead shrub']
  ).length === 2
);

["andesite", "grass", "dirt", "dead shrub"], ["andesite", "grass", "dirt", "dead shrub"] 应返回 []

assert.sameMembers(
  diffArray(
    ['andesite', 'grass', 'dirt', 'dead shrub'],
    ['andesite', 'grass', 'dirt', 'dead shrub']
  ),
  []
);

["andesite", "grass", "dirt", "dead shrub"], ["andesite", "grass", "dirt", "dead shrub"] 应返回一个空数组。

assert(
  diffArray(
    ['andesite', 'grass', 'dirt', 'dead shrub'],
    ['andesite', 'grass', 'dirt', 'dead shrub']
  ).length === 0
);

[1, 2, 3, 5], [1, 2, 3, 4, 5] 应返回 [4]

assert.sameMembers(diffArray([1, 2, 3, 5], [1, 2, 3, 4, 5]), [4]);

[1, 2, 3, 5], [1, 2, 3, 4, 5] 应返回一个长度为 1 的数组。

assert(diffArray([1, 2, 3, 5], [1, 2, 3, 4, 5]).length === 1);

[1, "calf", 3, "piglet"], [1, "calf", 3, 4] 应返回 ["piglet", 4]

assert.sameMembers(diffArray([1, 'calf', 3, 'piglet'], [1, 'calf', 3, 4]), [
  'piglet',
  4
]);

[1, "calf", 3, "piglet"], [1, "calf", 3, 4] 应返回一个长度为 2 的数组。

assert(diffArray([1, 'calf', 3, 'piglet'], [1, 'calf', 3, 4]).length === 2);

[], ["snuffleupagus", "cookie monster", "elmo"] 应返回 ["snuffleupagus", "cookie monster", "elmo"]

assert.sameMembers(diffArray([], ['snuffleupagus', 'cookie monster', 'elmo']), [
  'snuffleupagus',
  'cookie monster',
  'elmo'
]);

[], ["snuffleupagus", "cookie monster", "elmo"] 应返回一个长度为 3 的数组。

assert(diffArray([], ['snuffleupagus', 'cookie monster', 'elmo']).length === 3);

[1, "calf", 3, "piglet"], [7, "filly"] 应返回 [1, "calf", 3, "piglet", 7, "filly"]

assert.sameMembers(diffArray([1, 'calf', 3, 'piglet'], [7, 'filly']), [
  1,
  'calf',
  3,
  'piglet',
  7,
  'filly'
]);

[1, "calf", 3, "piglet"], [7, "filly"] 应返回一个长度为 6 的数组。

assert(diffArray([1, 'calf', 3, 'piglet'], [7, 'filly']).length === 6);

--solutions--