52 lines
951 B
Markdown
52 lines
951 B
Markdown
---
|
||
id: 5900f38f1000cf542c50fea2
|
||
title: 问题35:循环素数
|
||
challengeType: 5
|
||
videoUrl: ''
|
||
---
|
||
|
||
# --description--
|
||
|
||
这个数字197被称为循环素数,因为数字的所有旋转:197,971和719本身都是素数。在100:2,3,5,7,11,13,17,31,37,71,73,79和97之下有十三个这样的素数。在n下面有多少个圆形素数,而100 <= n < = 1000000?
|
||
|
||
# --hints--
|
||
|
||
`circularPrimes(100)`应该返回13。
|
||
|
||
```js
|
||
assert(circularPrimes(100) == 13);
|
||
```
|
||
|
||
`circularPrimes(100000)`应该返回43。
|
||
|
||
```js
|
||
assert(circularPrimes(100000) == 43);
|
||
```
|
||
|
||
`circularPrimes(250000)`应该返回45。
|
||
|
||
```js
|
||
assert(circularPrimes(250000) == 45);
|
||
```
|
||
|
||
`circularPrimes(500000)`应该返回49。
|
||
|
||
```js
|
||
assert(circularPrimes(500000) == 49);
|
||
```
|
||
|
||
`circularPrimes(750000)`应该返回49。
|
||
|
||
```js
|
||
assert(circularPrimes(750000) == 49);
|
||
```
|
||
|
||
`circularPrimes(1000000)`应该返回55。
|
||
|
||
```js
|
||
assert(circularPrimes(1000000) == 55);
|
||
```
|
||
|
||
# --solutions--
|
||
|