71 lines
1.2 KiB
Markdown
71 lines
1.2 KiB
Markdown
---
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id: 5a23c84252665b21eecc7ec1
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title: 迭代的数字平方
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challengeType: 5
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videoUrl: ''
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---
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# --description--
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如果添加自然数（大于零的整数）的数字的平方，则始终以1或89结尾：
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```
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15 - > 26 - > 40 - > 16 - > 37 - > 58 - > 89
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7 - > 49 - > 97 - > 130 - > 10 - > 1
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```
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编写一个函数，该函数将数字作为参数，并在执行上述过程后返回1或89。
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# --hints--
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`iteratedSquare`应该是一个函数。
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```js
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assert(typeof iteratedSquare == 'function');
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```
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`iteratedSquare(4)`应该返回一个数字。
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```js
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assert(typeof iteratedSquare(4) == 'number');
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```
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`iteratedSquare(4)`应该返回`89` 。
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```js
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assert.equal(iteratedSquare(4), 89);
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```
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`iteratedSquare(7)`应该返回`1` 。
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```js
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assert.equal(iteratedSquare(7), 1);
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```
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`iteratedSquare(15)`应该返回`89` 。
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```js
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assert.equal(iteratedSquare(15), 89);
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```
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`iteratedSquare(20)`应该返回`89` 。
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```js
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assert.equal(iteratedSquare(20), 89);
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```
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`iteratedSquare(70)`应该返回`1` 。
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```js
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assert.equal(iteratedSquare(70), 1);
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```
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`iteratedSquare(100)`应该返回`1` 。
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```js
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assert.equal(iteratedSquare(100), 1);
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```
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# --solutions--
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