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freeCodeCamp/curriculum/challenges/chinese/10-coding-interview-prep/rosetta-code/identity-matrix.md
Oliver Eyton-Williams ee1e8abd87 feat(curriculum): restore seed + solution to Chinese (#40683)
* feat(tools): add seed/solution restore script

* chore(curriculum): remove empty sections' markers

* chore(curriculum): add seed + solution to Chinese

* chore: remove old formatter

* fix: update getChallenges

parse translated challenges separately, without reference to the source

* chore(curriculum): add dashedName to English

* chore(curriculum): add dashedName to Chinese

* refactor: remove unused challenge property 'name'

* fix: relax dashedName requirement

* fix: stray tag

Remove stray `pre` tag from challenge file.

Signed-off-by: nhcarrigan <nhcarrigan@gmail.com>

Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
2021-01-12 19:31:00 -07:00

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---
id: 5a23c84252665b21eecc7eb1
title: 身份矩阵
challengeType: 5
videoUrl: ''
dashedName: identity-matrix
---
# --description--
*单位矩阵*是大小为\\n \\次n \\)的方阵,其中对角元素都是**1** s1所有其他元素都是**0** s。 \\ begin {bmatrix} 100 \\ cr 010 \\ cr 001 \\ cr \\ end {bmatrix}编写一个以数字'n'作为参数并返回单位矩阵的函数订单nx n。
# --hints--
`idMatrix`应该是一个功能。
```js
assert(typeof idMatrix == 'function');
```
`idMatrix(1)`应该返回一个数组。
```js
assert(Array.isArray(idMatrix(1)));
```
`idMatrix(1)`应返回`"+JSON.stringify(results[0])+"`
```js
assert.deepEqual(idMatrix(1), results[0]);
```
`idMatrix(2)`应返回`"+JSON.stringify(results[1])+"`
```js
assert.deepEqual(idMatrix(2), results[1]);
```
`idMatrix(3)`应返回`"+JSON.stringify(results[2])+"`
```js
assert.deepEqual(idMatrix(3), results[2]);
```
`idMatrix(4)`应返回`"+JSON.stringify(results[3])+"`
```js
assert.deepEqual(idMatrix(4), results[3]);
```
# --seed--
## --after-user-code--
```js
let results=[[ [ 1 ] ],
[ [ 1, 0 ], [ 0, 1 ] ],
[ [ 1, 0, 0 ], [ 0, 1, 0 ], [ 0, 0, 1 ] ],
[ [ 1, 0, 0, 0 ], [ 0, 1, 0, 0 ], [ 0, 0, 1, 0 ], [ 0, 0, 0, 1 ] ]]
```
## --seed-contents--
```js
function idMatrix(n) {
}
```
# --solutions--
```js
function idMatrix(n) {
return Array.apply(null, new Array(n)).map(function (x, i, xs) {
return xs.map(function (_, k) {
return i === k ? 1 : 0;
})
});
}
```