2.6 KiB
2.6 KiB
id, title, challengeType, forumTopicId, localeTitle
id | title | challengeType | forumTopicId | localeTitle |
---|---|---|---|---|
587d7fb9367417b2b2512c12 | Chain Search Query Helpers to Narrow Search Results | 2 | 301533 | 通过链式调用搜索查询辅助函数来缩小搜索结果 |
Description
Model.find()
(或者别的搜索方法)的最后一个参数传入回调函数, 查询将不会执行。你可以将查询条件存储在变量中供以后使用,我们也可以通过链式调用这类变量来构建新的查询字段。实际的数据库操作会在最终调用 .exec()
方法时执行。需要注意的是,你必须给 exec()
传一个回调方法。Mongoose 为我们提供了许多查询辅助函数, 这里我们使用最著名的一种。
Instructions
burrito
的人并按 name
进行排序。同时,我们需要隐藏他们的 age
属性。结果应限制在两个 document 内。请链式调用 .find()
、.sort()
、.limit()
和 .select()
。最后调用 .exec()
,并传入给它传入 done(err, data)
回调函数。
Tests
tests:
- text: 链接查询辅助函数应该成功
testString: 'getUserInput => $.ajax({url: getUserInput(''url'') + ''/_api/query-tools'', type: ''POST'', contentType:''application/json'', data: JSON.stringify([{name: ''Pablo'', age: 26, favoriteFoods: [''burrito'', ''hot-dog'']}, {name: ''Bob'', age: 23, favoriteFoods: [''pizza'', ''nachos'']}, {name: ''Ashley'', age: 32, favoriteFoods: [''steak'', ''burrito'']}, {name: ''Mario'', age: 51, favoriteFoods: [''burrito'', ''prosciutto'']} ]) }).then(data => { assert.isArray(data, ''the response should be an Array''); assert.equal(data.length, 2, ''the data array length is not what expected''); assert.notProperty(data[0], ''age'', ''The returned first item has too many properties''); assert.equal(data[0].name, ''Ashley'', ''The returned first item name is not what expected''); assert.notProperty(data[1], ''age'', ''The returned second item has too many properties''); assert.equal(data[1].name, ''Mario'', ''The returned second item name is not what expected'');}, xhr => { throw new Error(xhr.responseText); })'
Challenge Seed
Solution
/**
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*/