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freeCodeCamp/curriculum/challenges/chinese/08-coding-interview-prep/rosetta-code/ackermann-function.chinese.md

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---
title: Ackermann function
id: 594810f028c0303b75339acf
challengeType: 5
videoUrl: ''
localeTitle: 阿克曼功能
---
## Description
<section id="description"><p> Ackermann函数是递归函数的典型示例尤其值得注意的是它不是原始递归函数。它的值增长非常快其调用树的大小也是如此。 </p><p> Ackermann函数通常定义如下 </p> $$ Amn= \ begin {cases} n + 1\ mbox {if} m = 0 \\ Am-1,1\ mbox {if} m&gt; 0 \ mbox {和} n = 0 \\ Am-1Amn-1\ mbox {if} m&gt; 0 \ mbox {和} n&gt; 0. \ end {cases} $$ <p>它的论点永远不会消极,它总是终止。编写一个返回$ Amn$的值的函数。任意精度是首选(因为函数增长如此之快),但不是必需的。 </p></section>
## Instructions
<section id="instructions">
</section>
## Tests
<section id='tests'>
```yml
tests:
- text: <code>ack</code>是一个功能。
testString: 'assert(typeof ack === "function", "<code>ack</code> is a function.");'
- text: '<code>ack(0, 0)</code>应该返回1。'
testString: 'assert(ack(0, 0) === 1, "<code>ack(0, 0)</code> should return 1.");'
- text: '<code>ack(1, 1)</code>应该返回3。'
testString: 'assert(ack(1, 1) === 3, "<code>ack(1, 1)</code> should return 3.");'
- text: '<code>ack(2, 5)</code>应该返回13。'
testString: 'assert(ack(2, 5) === 13, "<code>ack(2, 5)</code> should return 13.");'
- text: '<code>ack(3, 3)</code>应该返回61。'
testString: 'assert(ack(3, 3) === 61, "<code>ack(3, 3)</code> should return 61.");'
```
</section>
## Challenge Seed
<section id='challengeSeed'>
<div id='js-seed'>
```js
function ack (m, n) {
// Good luck!
}
```
</div>
</section>
## Solution
<section id='solution'>
```js
// solution required
```
</section>