121 lines
3.8 KiB
Markdown
121 lines
3.8 KiB
Markdown
---
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id: 587d7b8e367417b2b2512b5c
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title: Understand Functional Programming Terminology
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challengeType: 1
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forumTopicId: 301240
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localeTitle: 了解函数式编程术语
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---
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## Description
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<section id='description'>
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FCC 团队需求有变更,现在想要两种茶:绿茶(green tea)和红茶(black tea)。事实证明,用户需求变更是很常见的。
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基于以上信息,我们需要重构上一节挑战中的<code>getTea</code>函数来处理多种茶的请求。我们可以修改<code>getTea</code>接受一个函数作为参数,使它能够修改茶的类型。这让<code>getTea</code>更灵活,也使需求变更时为程序员提供更多控制权。
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首先,我们将介绍一些术语:
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<code>Callbacks</code>是被传递到另一个函数中调用的函数。你应该已经在其他函数中看过这个写法,例如在<code>filter</code>中,回调函数告诉 JavaScript 以什么规则过滤数组。
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函数就像其他正常值一样,可以赋值给变量、传递给另一个函数,或从其它函数返回,这种函数叫做<code>头等</code>函数。在 JavaScript 中,所有函数都是<code>头等</code>函数。
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将函数为参数或返回值的函数叫做<code>高阶</code>函数。
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当函数传递给另一个函数或从另一个函数返回时,那些传入或返回的函数可以叫做<code>lambda</code>。
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</section>
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## Instructions
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<section id='instructions'>
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准备 27 杯绿茶和 13 杯红茶,分别存入<code>tea4GreenTeamFCC</code>和<code>tea4BlackTeamFCC</code>变量。请注意,<code>getTea</code>函数已经变了,现在它接收一个函数作为第一个参数。
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注意:数据(茶的数量)作为最后一个参数。我们将在后面的课程中对此进行更多讨论。
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</section>
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## Tests
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<section id='tests'>
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```yml
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tests:
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- text: <code>tea4GreenTeamFCC</code>变量应存有为团队准备的 27 杯茶。
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testString: assert(tea4GreenTeamFCC.length === 27);
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- text: <code>tea4GreenTeamFCC</code>变量应存有绿茶。
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testString: assert(tea4GreenTeamFCC[0] === 'greenTea');
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- text: <code>tea4BlackTeamFCC</code>变量应存有 13 杯红茶。
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testString: assert(tea4BlackTeamFCC.length === 13);
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- text: <code>tea4BlackTeamFCC</code>变量应存有红茶。
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testString: assert(tea4BlackTeamFCC[0] === 'blackTea');
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```
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</section>
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## Challenge Seed
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<section id='challengeSeed'>
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<div id='js-seed'>
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```js
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/**
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* A long process to prepare green tea.
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* @return {string} A cup of green tea.
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**/
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const prepareGreenTea = () => 'greenTea';
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/**
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* A long process to prepare black tea.
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* @return {string} A cup of black tea.
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**/
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const prepareBlackTea = () => 'blackTea';
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/**
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* Get given number of cups of tea.
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* @param {function():string} prepareTea The type of tea preparing function.
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* @param {number} numOfCups Number of required cups of tea.
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* @return {Array<string>} Given amount of tea cups.
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**/
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const getTea = (prepareTea, numOfCups) => {
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const teaCups = [];
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for(let cups = 1; cups <= numOfCups; cups += 1) {
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const teaCup = prepareTea();
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teaCups.push(teaCup);
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}
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return teaCups;
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};
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// Add your code below this line
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const tea4GreenTeamFCC = null; // :(
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const tea4BlackTeamFCC = null; // :(
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// Add your code above this line
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console.log(
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tea4GreenTeamFCC,
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tea4BlackTeamFCC
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);
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```
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</div>
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</section>
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## Solution
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<section id='solution'>
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```js
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// solution required
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const prepareGreenTea = () => 'greenTea';
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const prepareBlackTea = () => 'blackTea';
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const getTea = (prepareTea, numOfCups) => {
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const teaCups = [];
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for(let cups = 1; cups <= numOfCups; cups += 1) {
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const teaCup = prepareTea();
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teaCups.push(teaCup);
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}
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return teaCups;
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};
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const tea4BlackTeamFCC = getTea(prepareBlackTea, 13);
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const tea4GreenTeamFCC = getTea(prepareGreenTea, 27);
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```
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</section>
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