freeCodeCamp/problem-50-consecutive-prime-sum.md at 41b7a331008a97d20155c3752b3beb530375ab99

Oliver Eyton-Williams 41b7a33100

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2020-09-29 22:09:05 +02:00

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id, challengeType, title, videoUrl, localeTitle

id	challengeType	title	videoUrl	localeTitle
5900f39e1000cf542c50feb1	5	Problem 50: Consecutive prime sum		问题50：连续的总和

Description

素数41可以写成六个连续素数的总和：41 = 2 + 3 + 5 + 7 + 11 + 13这是连续素数的最长和，它加到低于一百的素数。连续素数低于1000的连续素数加上一个素数，包含21个项，等于953.哪个素数低于一百万，可以写成最连续素数的总和？

Instructions

Tests

tests:
  - text: <code>consecutivePrimeSum(1000)</code>应该返回953。
    testString: assert.strictEqual(consecutivePrimeSum(1000), 953);
  - text: <code>consecutivePrimeSum(1000000)</code>应该返回997651。
    testString: assert.strictEqual(consecutivePrimeSum(1000000), 997651);

Challenge Seed

function consecutivePrimeSum(limit) {
  // Good luck!
  return true;
}

consecutivePrimeSum(1000000);

Solution

// solution required

/section>

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