898 B
		
	
	
	
	
	
	
	
			
		
		
	
	
			898 B
		
	
	
	
	
	
	
	
title
| title | 
|---|
| Multiples of 3 and 5 | 
Problem 1: Multiples of 3 and 5
Method:
- We can find if a number is divisble by another number with the help of 
%modulo operator. num1 % num2returns0if there's no remainder while doingnum1/num2.- Starting from 
i = 3because that's the first number that's divisble by 3 or 5, we loop through till thenumberprovided. - If the number is divisible either by 3 or 5, we add that to the variable 
sumand finally return it. 
Solution:
function multiplesOf3and5(number) {
  let sum = 0, i = 3;
  while (i < number){
    if (i % 3 == 0 || i % 5 == 0) sum += i;
    i++;
  }
  return sum;
}