51 lines
1.3 KiB
Markdown
51 lines
1.3 KiB
Markdown
---
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id: 5900f3df1000cf542c50fef1
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title: 'Problem 115: Counting block combinations II'
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challengeType: 5
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forumTopicId: 301741
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dashedName: problem-115-counting-block-combinations-ii
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---
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# --description--
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A row measuring `n` units in length has red blocks with a minimum length of `m` units placed on it, such that any two red blocks (which are allowed to be different lengths) are separated by at least one black square.
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Let the fill-count function, $F(m, n)$, represent the number of ways that a row can be filled.
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For example, $F(3, 29) = 673135$ and $F(3, 30) = 1089155$.
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That is, for m = 3, it can be seen that n = 30 is the smallest value for which the fill-count function first exceeds one million.
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In the same way, for m = 10, it can be verified that $F(10, 56) = 880711$ and $F(10, 57) = 1148904$, so n = 57 is the least value for which the fill-count function first exceeds one million.
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For m = 50, find the least value of `n` for which the fill-count function first exceeds one million.
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**Note:** This is a more difficult version of Problem 114.
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# --hints--
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`countingBlockTwo()` should return `168`.
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```js
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assert.strictEqual(countingBlockTwo(), 168);
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```
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# --seed--
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## --seed-contents--
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```js
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function countingBlockTwo() {
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return true;
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}
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countingBlockTwo();
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```
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# --solutions--
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```js
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// solution required
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```
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