67 lines
		
	
	
		
			2.4 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
			
		
		
	
	
			67 lines
		
	
	
		
			2.4 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
| ---
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| id: 5900f50b1000cf542c51001d
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| title: 'Problem 414: Kaprekar constant'
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| challengeType: 5
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| forumTopicId: 302083
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| dashedName: problem-414-kaprekar-constant
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| ---
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| 
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| # --description--
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| 
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| 6174 is a remarkable number; if we sort its digits in increasing order and subtract that number from the number you get when you sort the digits in decreasing order, we get $7641 - 1467 = 6174$.
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| 
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| Even more remarkable is that if we start from any 4 digit number and repeat this process of sorting and subtracting, we'll eventually end up with 6174 or immediately with 0 if all digits are equal.
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| 
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| This also works with numbers that have less than 4 digits if we pad the number with leading zeroes until we have 4 digits.
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| 
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| E.g. let's start with the number 0837:
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| 
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| $$\begin{align}
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|   & 8730 - 0378 = 8352 \\\\
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|   & 8532 - 2358 = 6174
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| \end{align}$$
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| 
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| 6174 is called the Kaprekar constant. The process of sorting and subtracting and repeating this until either 0 or the Kaprekar constant is reached is called the Kaprekar routine.
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| 
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| We can consider the Kaprekar routine for other bases and number of digits. Unfortunately, it is not guaranteed a Kaprekar constant exists in all cases; either the routine can end up in a cycle for some input numbers or the constant the routine arrives at can be different for different input numbers. However, it can be shown that for 5 digits and a base $b = 6t + 3 ≠ 9$, a Kaprekar constant exists.
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| 
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| E.g. base 15: ${(10, 4, 14, 9, 5)}\_{15}$ base 21: $(14, 6, 20, 13, 7)_{21}$
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| 
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| Define $C_b$ to be the Kaprekar constant in base $b$ for 5 digits. Define the function $sb(i)$ to be:
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| 
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| - 0 if $i = C_b$ or if $i$ written in base $b$ consists of 5 identical digits
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| - the number of iterations it takes the Kaprekar routine in base $b$ to arrive at $C_b$, otherwise
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| 
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| Note that we can define $sb(i)$ for all integers $i < b^5$. If $i$ written in base $b$ takes less than 5 digits, the number is padded with leading zero digits until we have 5 digits before applying the Kaprekar routine.
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| 
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| Define $S(b)$ as the sum of $sb(i)$ for $0 < i < b^5$. E.g. $S(15) = 5\\,274\\,369$ $S(111) = 400\\,668\\,930\\,299$
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| 
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| Find the sum of $S(6k + 3)$ for $2 ≤ k ≤ 300$. Give the last 18 digits as your answer.
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| 
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| # --hints--
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| 
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| `kaprekarConstant()` should return `552506775824935500`.
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| 
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| ```js
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| assert.strictEqual(kaprekarConstant(), 552506775824935500);
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| ```
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| 
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| # --seed--
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| 
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| ## --seed-contents--
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| 
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| ```js
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| function kaprekarConstant() {
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| 
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|   return true;
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| }
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| 
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| kaprekarConstant();
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| ```
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| 
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| # --solutions--
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| 
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| ```js
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| // solution required
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| ```
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