freeCodeCamp/curriculum/challenges/chinese/10-coding-interview-prep/project-euler/problem-108-diophantine-reciprocals-i.md

id, challengeType, videoUrl, localeTitle

id	challengeType	videoUrl	localeTitle
5900f3d91000cf542c50feeb	5		问题108：丢番图互惠I

Description

在下面的等式中，x，y和n是正整数。 1 / x + 1 / y = 1 / n对于n = 4，恰好有三种不同的解：1/5 + 1/20 = 1/4
1/6 + 1/12 = 1/4
1/8 + 1/8 = 1/4不同解的数量超过一千的n的最小值是多少？

Instructions

Tests

tests:
  - text: diophantineOne <code>diophantineOne()</code>应返回180180。
    testString: assert.strictEqual(diophantineOne(), 180180);

Challenge Seed

function diophantineOne() {
  // Good luck!
  return true;
}

diophantineOne();

Solution

// solution required

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