1.7 KiB
1.7 KiB
id, challengeType, videoUrl, localeTitle
id | challengeType | videoUrl | localeTitle |
---|---|---|---|
599d15309e88c813a40baf58 | 5 | 熵 |
Description
计算给定输入字符串的香农熵H.
给定谨慎的随机变量$ X $,它是$ N $“符号”(总字符)的字符串,由$ n $个不同的字符组成(对于二进制,n = 2),位/符号中X的香农熵是:
$ H_2(X)= - \ sum_ {i = 1} ^ n \ frac {count_i} {N} \ log_2 \ left(\ frac {count_i} {N} \ right)$
其中$ count_i $是字符$ n_i $的计数。
Instructions
Tests
tests:
- text: <code>entropy</code>是一种功能。
testString: assert(typeof entropy === 'function');
- text: <code>entropy("0")</code>应该返回<code>0</code>
testString: assert.equal(entropy('0'), 0);
- text: <code>entropy("01")</code>应该返回<code>1</code>
testString: assert.equal(entropy('01'), 1);
- text: <code>entropy("0123")</code>应该返回<code>2</code>
testString: assert.equal(entropy('0123'), 2);
- text: <code>entropy("01234567")</code>应该返回<code>3</code>
testString: assert.equal(entropy('01234567'), 3);
- text: <code>entropy("0123456789abcdef")</code>应返回<code>4</code>
testString: assert.equal(entropy('0123456789abcdef'), 4);
- text: <code>entropy("1223334444")</code>应返回<code>1.8464393446710154</code>
testString: assert.equal(entropy('1223334444'), 1.8464393446710154);
Challenge Seed
function entropy (s) {
// Good luck!
}
Solution
// solution required
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