* Use dfn tags * remove misused <dfn> tags * Revert "remove misused <dfn> tags" This reverts commit b24968a96810f618d831410ac90a0bc452ebde50. * Update curriculum/challenges/english/01-responsive-web-design/basic-html-and-html5/fill-in-the-blank-with-placeholder-text.english.md Co-Authored-By: Randell Dawson <5313213+RandellDawson@users.noreply.github.com> * Make "array" lowercase Co-Authored-By: Randell Dawson <5313213+RandellDawson@users.noreply.github.com> * Fix dfn usage * Address last dfn tags
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id, title, challengeType, videoUrl, forumTopicId
id | title | challengeType | videoUrl | forumTopicId |
---|---|---|---|---|
bd7123c9c549eddfaeb5bdef | Use Bracket Notation to Find the First Character in a String | 1 | https://scrimba.com/c/ca8JwhW | 18341 |
Description
index
within a string.
Most modern programming languages, like JavaScript, don't start counting at 1 like humans do. They start at 0. This is referred to as Zero-based indexing.
For example, the character at index 0 in the word "Charles" is "C". So if var firstName = "Charles"
, you can get the value of the first letter of the string by using firstName[0]
.
Instructions
lastName
variable and assign it to firstLetterOfLastName
.
HintTry looking at the
firstLetterOfFirstName
variable declaration if you get stuck.
Tests
tests:
- text: The <code>firstLetterOfLastName</code> variable should have the value of <code>L</code>.
testString: assert(firstLetterOfLastName === 'L');
- text: You should use bracket notation.
testString: assert(code.match(/firstLetterOfLastName\s*?=\s*?lastName\[.*?\]/));
Challenge Seed
// Example
var firstLetterOfFirstName = "";
var firstName = "Ada";
firstLetterOfFirstName = firstName[0];
// Setup
var firstLetterOfLastName = "";
var lastName = "Lovelace";
// Only change code below this line
firstLetterOfLastName = lastName;
After Test
(function(v){return v;})(firstLetterOfLastName);
Solution
var firstLetterOfLastName = "";
var lastName = "Lovelace";
// Only change code below this line
firstLetterOfLastName = lastName[0];