102 lines
		
	
	
		
			3.3 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
			
		
		
	
	
			102 lines
		
	
	
		
			3.3 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
| ---
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| id: 5900f3a31000cf542c50feb6
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| challengeType: 5
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| title: 'Problem 55: Lychrel numbers'
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| ---
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| 
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| ## Description
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| <section id='description'>
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| If we take 47, reverse and add, 47 + 74 = 121, which is palindromic.
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| Not all numbers produce palindromes so quickly. For example,
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| 349 + 943 = 1292,
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| 1292 + 2921 = 4213
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| 4213 + 3124 = 7337
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| That is, 349 took three iterations to arrive at a palindrome.
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| Although no one has proved it yet, it is thought that some numbers, like 196, never produce a palindrome. A number that never forms a palindrome through the reverse and add process is called a Lychrel number. Due to the theoretical nature of these numbers, and for the purpose of this problem, we shall assume that a number is Lychrel until proven otherwise. In addition you are given that for every number below ten-thousand, it will either (i) become a palindrome in less than fifty iterations, or, (ii) no one, with all the computing power that exists, has managed so far to map it to a palindrome. In fact, 10677 is the first number to be shown to require over fifty iterations before producing a palindrome: 4668731596684224866951378664 (53 iterations, 28-digits).
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| Surprisingly, there are palindromic numbers that are themselves Lychrel numbers; the first example is 4994.
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| How many Lychrel numbers are there below <code>num</code>?
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| NOTE: Wording was modified slightly on 24 April 2007 to emphasise the theoretical nature of Lychrel numbers.
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| </section>
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| 
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| ## Instructions
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| <section id='instructions'>
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| 
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| </section>
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| 
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| ## Tests
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| <section id='tests'>
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| 
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| ```yml
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| tests:
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|   - text: <code>countLychrelNumbers(1000)</code> should return 13.
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|     testString: 'assert.strictEqual(countLychrelNumbers(1000), 13, "<code>countLychrelNumbers(1000)</code> should return 13.");'
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|   - text: <code>countLychrelNumbers(5000)</code> should return 76.
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|     testString: 'assert.strictEqual(countLychrelNumbers(5000), 76, "<code>countLychrelNumbers(5000)</code> should return 76.");'
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|   - text: <code>countLychrelNumbers(10000)</code> should return 249.
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|     testString: 'assert.strictEqual(countLychrelNumbers(10000), 249, "<code>countLychrelNumbers(10000)</code> should return 249.");'
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|   - text: Your function should count all Lychrel numbers.
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|     testString: 'assert.strictEqual(countLychrelNumbers(3243), 39, "Your function should count all Lychrel numbers.");'
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|   - text: Your function should pass all test cases.
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|     testString: 'assert.strictEqual(countLychrelNumbers(7654), 140, "Your function should pass all test cases.");'
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| 
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| ```
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| 
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| </section>
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| 
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| ## Challenge Seed
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| <section id='challengeSeed'>
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| 
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| <div id='js-seed'>
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| 
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| ```js
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| function countLychrelNumbers(num) {
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|   // Good luck!
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|   return true;
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| }
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| 
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| countLychrelNumbers(10000);
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| ```
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| 
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| </div>
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| 
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| 
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| 
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| </section>
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| 
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| ## Solution
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| <section id='solution'>
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| 
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| 
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| ```js
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| const countLychrelNumbers = (size) => {
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|   const numReverse = (num) => {
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|     return Number(num.toString().split('').reverse().join(''));
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|   };
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|   const isPalin = (num) => {
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|     if (numReverse(num) === num) {
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|       return true;
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|     }
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|     return false;
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|   };
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|   let total = 0;
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|   for (let i = 1; i < size; i++) {
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|     let loopCount = 1;
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|     let sum = i;
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|     while (loopCount < 50) {
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|       sum = sum + numReverse(sum);
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|       if (isPalin(sum)) {
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|         break;
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|       } else {
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|         loopCount++;
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|       }
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|     }
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|     if (loopCount === 50) {
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|       total++;
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|     }
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|   }
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|   return total;
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| }
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| ```
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| 
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| </section>
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