* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
		
			
				
	
	
		
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			1.3 KiB
		
	
	
	
		
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			82 lines
		
	
	
		
			1.3 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
| ---
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| id: 5900f3761000cf542c50fe89
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| title: 'Problem 10: Summation of primes'
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| challengeType: 5
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| forumTopicId: 301723
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| dashedName: problem-10-summation-of-primes
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| ---
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| 
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| # --description--
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| 
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| The sum of the primes below 10 is 2 + 3 + 5 + 7 = 17.
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| 
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| Find the sum of all the primes below `n`.
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| 
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| # --hints--
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| 
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| `primeSummation(17)` should return a number.
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| 
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| ```js
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| assert(typeof primeSummation(17) === 'number');
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| ```
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| 
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| `primeSummation(17)` should return 41.
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| 
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| ```js
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| assert.strictEqual(primeSummation(17), 41);
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| ```
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| 
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| `primeSummation(2001)` should return 277050.
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| 
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| ```js
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| assert.strictEqual(primeSummation(2001), 277050);
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| ```
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| 
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| `primeSummation(140759)` should return 873608362.
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| 
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| ```js
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| assert.strictEqual(primeSummation(140759), 873608362);
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| ```
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| 
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| `primeSummation(2000000)` should return 142913828922.
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| 
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| ```js
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| assert.strictEqual(primeSummation(2000000), 142913828922);
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| ```
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| 
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| # --seed--
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| 
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| ## --seed-contents--
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| 
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| ```js
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| function primeSummation(n) {
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| 
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|   return true;
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| }
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| 
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| primeSummation(2000000);
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| ```
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| 
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| # --solutions--
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| 
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| ```js
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| function primeSummation(n) {
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|   if (n < 3) { return 0 };
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|   let nums = [0, 0, 2];
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|   for (let i = 3; i < n; i += 2){
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|     nums.push(i);
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|     nums.push(0);
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|   }
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|   let sum = 2;
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|   for (let i = 3; i < n; i += 2){
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|     if (nums[i] !== 0){
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|       sum += nums[i];
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|       for (let j = i*i; j < n; j += i){
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|         nums[j] = 0;
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|       }
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|     }
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|   }
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|   return sum;
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| }
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| ```
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