Oliver Eyton-Williams ee1e8abd87
feat(curriculum): restore seed + solution to Chinese (#40683)
* feat(tools): add seed/solution restore script

* chore(curriculum): remove empty sections' markers

* chore(curriculum): add seed + solution to Chinese

* chore: remove old formatter

* fix: update getChallenges

parse translated challenges separately, without reference to the source

* chore(curriculum): add dashedName to English

* chore(curriculum): add dashedName to Chinese

* refactor: remove unused challenge property 'name'

* fix: relax dashedName requirement

* fix: stray tag

Remove stray `pre` tag from challenge file.

Signed-off-by: nhcarrigan <nhcarrigan@gmail.com>

Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
2021-01-12 19:31:00 -07:00

1.2 KiB

id, title, challengeType, videoUrl, forumTopicId, dashedName
id title challengeType videoUrl forumTopicId dashedName
56533eb9ac21ba0edf2244b2 复合赋值之 /= 1 https://scrimba.com/c/c2QvKT2 16659 compound-assignment-with-augmented-division

--description--

/=操作符是让变量与另一个数相除并赋值。

myVar = myVar / 5;

变量myVar等于自身除以5的值。等价于:

myVar /= 5;

--instructions--

使用/=操作符实现同样的效果。

--hints--

a应该等于4

assert(a === 4);

b应该等于27

assert(b === 27);

c应该等于3

assert(c === 3);

应该对每个变量使用/=操作符。

assert(code.match(/\/=/g).length === 3);

不要修改注释上面的代码。

assert(
  /var a = 48;/.test(code) &&
    /var b = 108;/.test(code) &&
    /var c = 33;/.test(code)
);

--seed--

--after-user-code--

(function(a,b,c){ return "a = " + a + ", b = " + b + ", c = " + c; })(a,b,c);

--seed-contents--

var a = 48;
var b = 108;
var c = 33;

// Only change code below this line
a = a / 12;
b = b / 4;
c = c / 11;

--solutions--

var a = 48;
var b = 108;
var c = 33;

a /= 12;
b /= 4;
c /= 11;