Oliver Eyton-Williams ee1e8abd87
feat(curriculum): restore seed + solution to Chinese (#40683)
* feat(tools): add seed/solution restore script

* chore(curriculum): remove empty sections' markers

* chore(curriculum): add seed + solution to Chinese

* chore: remove old formatter

* fix: update getChallenges

parse translated challenges separately, without reference to the source

* chore(curriculum): add dashedName to English

* chore(curriculum): add dashedName to Chinese

* refactor: remove unused challenge property 'name'

* fix: relax dashedName requirement

* fix: stray tag

Remove stray `pre` tag from challenge file.

Signed-off-by: nhcarrigan <nhcarrigan@gmail.com>

Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
2021-01-12 19:31:00 -07:00

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---
id: 587d7da9367417b2b2512b66
title: 使用 concat 方法组合两个数组
challengeType: 1
forumTopicId: 301229
dashedName: combine-two-arrays-using-the-concat-method
---
# --description--
`Concatenation`意思是将元素连接到尾部。同理JavaScript 为字符串和数组提供了`concat`方法。对数组来说,在一个数组上调用`concat`方法,然后提供另一个数组作为参数添加到第一个数组末尾,返回一个新数组,不会改变任何一个原始数组。举个例子:
```js
[1, 2, 3].concat([4, 5, 6]);
// 返回新数组 [1, 2, 3, 4, 5, 6]
```
# --instructions--
`nonMutatingConcat`函数里使用`concat`,将`attach`拼接到`original`尾部,返回拼接后的数组。
# --hints--
应该使用`concat`方法。
```js
assert(code.match(/\.concat/g));
```
不能改变`first`数组。
```js
assert(JSON.stringify(first) === JSON.stringify([1, 2, 3]));
```
不能改变`second`数组。
```js
assert(JSON.stringify(second) === JSON.stringify([4, 5]));
```
`nonMutatingConcat([1, 2, 3], [4, 5])`应返回`[1, 2, 3, 4, 5]`
```js
assert(
JSON.stringify(nonMutatingConcat([1, 2, 3], [4, 5])) ===
JSON.stringify([1, 2, 3, 4, 5])
);
```
# --seed--
## --seed-contents--
```js
function nonMutatingConcat(original, attach) {
// Only change code below this line
// Only change code above this line
}
var first = [1, 2, 3];
var second = [4, 5];
nonMutatingConcat(first, second);
```
# --solutions--
```js
function nonMutatingConcat(original, attach) {
// Only change code below this line
return original.concat(attach);
// Only change code above this line
}
var first = [1, 2, 3];
var second = [4, 5];
nonMutatingConcat(first, second);
```