* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
86 lines
1.9 KiB
Markdown
86 lines
1.9 KiB
Markdown
---
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id: 5d712346c441eddfaeb5bdef
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title: 匹配所有数字
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challengeType: 1
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forumTopicId: 18181
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dashedName: match-all-numbers
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---
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# --description--
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已经了解了常见字符串匹配模式的元字符,如字母数字。另一个常见的匹配模式是只寻找数字。
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查找数字字符的缩写是`\d`,注意是小写的`d`。这等同于元字符`[0-9]`,它查找 0 到 9 之间任意数字的单个字符。
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# --instructions--
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使用缩写`\d`来计算电影标题中有多少个数字。书面数字("six" 而不是 6)不计算在内。
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# --hints--
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你的正则表达式应该使用缩写来匹配数字字符。
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```js
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assert(/\\d/.test(numRegex.source));
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```
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你的正则表达式应该使用全局状态修正符。
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```js
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assert(numRegex.global);
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```
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你的正则表达式应该在`'9'`中匹配到 1 个数字。
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```js
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assert('9'.match(numRegex).length == 1);
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```
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你的正则表达式应该在`'Catch 22'`中匹配到 2 个数字。
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```js
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assert('Catch 22'.match(numRegex).length == 2);
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```
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你的正则表达式应该在`'101 Dalmatians'`中匹配到 3 个数字。
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```js
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assert('101 Dalmatians'.match(numRegex).length == 3);
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```
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你的正则表达式在`'One, Two, Three'`中应该匹配不到数字。
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```js
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assert('One, Two, Three'.match(numRegex) == null);
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```
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你的正则表达式应该在`'21 Jump Street'`中匹配到 2 个数字。
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```js
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assert('21 Jump Street'.match(numRegex).length == 2);
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```
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你的正则表达式应该在`"2001: A Space Odyssey"`中匹配到 4 个数字。
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```js
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assert('2001: A Space Odyssey'.match(numRegex).length == 4);
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```
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# --seed--
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## --seed-contents--
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```js
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let movieName = "2001: A Space Odyssey";
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let numRegex = /change/; // Change this line
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let result = movieName.match(numRegex).length;
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```
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# --solutions--
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```js
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let movieName = "2001: A Space Odyssey";
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let numRegex = /\d/g; // Change this line
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let result = movieName.match(numRegex).length;
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```
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