Oliver Eyton-Williams ee1e8abd87

feat(curriculum): restore seed + solution to Chinese (#40683 )

* feat(tools): add seed/solution restore script

* chore(curriculum): remove empty sections' markers

* chore(curriculum): add seed + solution to Chinese

* chore: remove old formatter

* fix: update getChallenges

parse translated challenges separately, without reference to the source

* chore(curriculum): add dashedName to English

* chore(curriculum): add dashedName to Chinese

* refactor: remove unused challenge property 'name'

* fix: relax dashedName requirement

* fix: stray tag

Remove stray `pre` tag from challenge file.

Signed-off-by: nhcarrigan <nhcarrigan@gmail.com>

Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>

2021-01-12 19:31:00 -07:00

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id, title, challengeType, videoUrl, dashedName

id	title	challengeType	videoUrl	dashedName
5900f3ee1000cf542c50ff00	问题130：具有主要repunit属性的复合材料	5		problem-130-composites-with-prime-repunit-property

--description--

完全由1组成的数字称为repunit。我们将R（k）定义为长度k的重新定位;例如，R（6）= 111111.假设n是正整数且GCD（n，10）= 1，则可以证明总是存在一个值k，其中R（k）可被n整除让A（n）成为k的最小值;例如，A（7）= 6和A（41）= 5.对于所有素数，p> 5，p-1可以被A（p）整除。例如，当p = 41时，A（41）= 5，并且40可被5整除。但是，也有罕见的复合值，这也是正确的;前五个例子是91,259,451,481和703.找到n的前25个复合值之和，其中GCD（n，10）= 1，n-1可被A（n）整除。

--hints--

euler130()应返回149253。

assert.strictEqual(euler130(), 149253);

--seed--

--seed-contents--

function euler130() {

  return true;
}

euler130();

--solutions--

// solution required

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