Oliver Eyton-Williams ee1e8abd87

feat(curriculum): restore seed + solution to Chinese (#40683 )

* feat(tools): add seed/solution restore script

* chore(curriculum): remove empty sections' markers

* chore(curriculum): add seed + solution to Chinese

* chore: remove old formatter

* fix: update getChallenges

parse translated challenges separately, without reference to the source

* chore(curriculum): add dashedName to English

* chore(curriculum): add dashedName to Chinese

* refactor: remove unused challenge property 'name'

* fix: relax dashedName requirement

* fix: stray tag

Remove stray `pre` tag from challenge file.

Signed-off-by: nhcarrigan <nhcarrigan@gmail.com>

Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>

2021-01-12 19:31:00 -07:00

820 B

Raw Blame History

id, title, challengeType, videoUrl, dashedName

id	title	challengeType	videoUrl	dashedName
5900f3f21000cf542c50ff05	问题134：素对对连接	5		problem-134-prime-pair-connection

--description--

考虑连续的素数p1 = 19和p2 = 23.可以证实1219是最小的数字，使得最后的数字由p1形成，同时也可以被p2整除。实际上，除了p1 = 3和p2 = 5之外，对于每对连续质数，p2> p1，存在n的值，其中最后的数字由p1形成，n可以被p2整除。设S是n的这些值中最小的。找到每对连续质数的ΣS，其中5≤p1≤1000000。

--hints--

euler134()应该返回18613426663617120。

assert.strictEqual(euler134(), 18613426663617120);

--seed--

--seed-contents--

function euler134() {

  return true;
}

euler134();

--solutions--

// solution required

820 B Raw Blame History Unescape Escape