Oliver Eyton-Williams ee1e8abd87
feat(curriculum): restore seed + solution to Chinese (#40683)
* feat(tools): add seed/solution restore script

* chore(curriculum): remove empty sections' markers

* chore(curriculum): add seed + solution to Chinese

* chore: remove old formatter

* fix: update getChallenges

parse translated challenges separately, without reference to the source

* chore(curriculum): add dashedName to English

* chore(curriculum): add dashedName to Chinese

* refactor: remove unused challenge property 'name'

* fix: relax dashedName requirement

* fix: stray tag

Remove stray `pre` tag from challenge file.

Signed-off-by: nhcarrigan <nhcarrigan@gmail.com>

Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
2021-01-12 19:31:00 -07:00

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id, title, challengeType, videoUrl, dashedName
id title challengeType videoUrl dashedName
5900f37d1000cf542c50fe8f 问题16电源数字总和 5 problem-16-power-digit-sum

--description--

2 15= 32768其位数之和为3 + 2 + 7 + 6 + 8 = 26。 2 指数的数字总和是多少?

--hints--

powerDigitSum(15)应该返回26。

assert.strictEqual(powerDigitSum(15), 26);

powerDigitSum(128)应该返回166。

assert.strictEqual(powerDigitSum(128), 166);

powerDigitSum(1000)应返回1366。

assert.strictEqual(powerDigitSum(1000), 1366);

--seed--

--seed-contents--

function powerDigitSum(exponent) {

  return true;
}

powerDigitSum(15);

--solutions--

function powerDigitSum(exponent) {
  const bigNum = [1];
  let sum = 0;

  for (let i = 1; i <= exponent; i++) {
    let count = bigNum.length + 1;
    let overflow = 0;
    for (let j = 0; j < count; j++) {
      let digit = bigNum[j] || 0;
      digit = 2 * digit + overflow;

      if (digit > 9) {
        digit -= 10;
        overflow = 1;
      } else {
        overflow = 0;
      }

      bigNum[j] = digit;
    }
  }

  bigNum.forEach(function(num) {
    return sum += num;
  });

  return sum;
}