* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
49 lines
1.3 KiB
Markdown
49 lines
1.3 KiB
Markdown
---
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id: 5900f4281000cf542c50ff39
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title: 问题186:网络的连通性
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challengeType: 5
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videoUrl: ''
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dashedName: problem-186-connectedness-of-a-network
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---
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# --description--
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以下是来自拥有100万用户的繁忙电话系统的记录:
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RecNrCallerCalled120000710005326001835004393600863701497 .........来电者的电话号码和记录n中的被叫号码是来电者(n)= S2n-1和被叫(n)= S2n,其中S1,2,3,...来来自“Lagged Fibonacci Generator”:
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对于1≤k≤55,Sk = \[100003 - 200003k + 300007k3](模1000000)对于56≤k,Sk = \[Sk-24 + Sk-55](模1000000)
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如果Caller(n)= Called(n),则假定用户误操作并且呼叫失败;否则通话成功。
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从记录的开头,我们说如果X调用Y,则任何一对用户X和Y都是朋友,反之亦然。类似地,如果X是Y的朋友并且Y是Z的朋友,则X是Z的朋友的朋友;等等更长的链条。
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总理的电话号码是524287.经过多少次成功的电话,不计算误操作,99%的用户(包括PM)将成为总理的朋友,朋友的朋友等?
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# --hints--
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`euler186()`应返回2325629。
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```js
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assert.strictEqual(euler186(), 2325629);
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```
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# --seed--
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## --seed-contents--
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```js
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function euler186() {
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return true;
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}
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euler186();
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```
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# --solutions--
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```js
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// solution required
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```
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