Oliver Eyton-Williams ee1e8abd87

feat(curriculum): restore seed + solution to Chinese (#40683 )

* feat(tools): add seed/solution restore script

* chore(curriculum): remove empty sections' markers

* chore(curriculum): add seed + solution to Chinese

* chore: remove old formatter

* fix: update getChallenges

parse translated challenges separately, without reference to the source

* chore(curriculum): add dashedName to English

* chore(curriculum): add dashedName to Chinese

* refactor: remove unused challenge property 'name'

* fix: relax dashedName requirement

* fix: stray tag

Remove stray `pre` tag from challenge file.

Signed-off-by: nhcarrigan <nhcarrigan@gmail.com>

Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>

2021-01-12 19:31:00 -07:00

1.3 KiB

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id, title, challengeType, videoUrl, dashedName

id	title	challengeType	videoUrl	dashedName
5900f4ba1000cf542c50ffcd	问题334：溢出豆子	5		problem-334-spilling-the-beans

--description--

在柏拉图的天堂里，存在着无数个直线的碗。每个碗都包含一些或不包含有限数量的豆。一个孩子玩游戏，只允许一种移动：从任何碗中取出两个豆子，并在两个相邻的碗中放入一个豆子。当每个碗包含一个或没有豆时，游戏结束。

例如，考虑两个相邻的碗分别包含2个和3个豆，所有其他碗都是空的。以下八个动作将完成游戏：

您将获得以下序列：t0 = 123456。

  ti = ti-12 , if ti-1 is even ti-12 926252, if ti-1 is odd where ⌊x⌋ is the floor function and is the bitwise XOR operator. bi = ( ti mod 211) + 1.

最后一个序列的前两个项是b1 = 289和b2 = 145.如果我们从两个相邻碗中的b1和b2豆开始，则需要3419100次移动来完成游戏。

现在考虑1500个相邻的碗，分别包含b1，b2，...，b1500豆，所有其他碗都是空的。查看游戏结束前需要多少动作。

--hints--

euler334()应该返回150320021261690850。

assert.strictEqual(euler334(), 150320021261690850);

--seed--

--seed-contents--

function euler334() {

  return true;
}

euler334();

--solutions--

// solution required

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