* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
1.9 KiB
1.9 KiB
id, title, challengeType, videoUrl, dashedName
id | title | challengeType | videoUrl | dashedName |
---|---|---|---|---|
5900f39d1000cf542c50feb0 | 问题49:主要排列 | 5 | problem-49-prime-permutations |
--description--
算术序列1487,4817,8147,其中每个项增加3330,在两个方面是不寻常的:(i)三个项中的每一个都是素数,并且,(ii)每个4位数字是彼此的排列。没有由三个1位,2位或3位数的素数组成的算术序列,表现出这种性质,但还有另外一个4位数的增加序列。你通过连接这个序列中的三个术语来形成12位数字?
--hints--
primePermutations()
应该返回296962999629。
assert.strictEqual(primePermutations(), 296962999629);
--seed--
--seed-contents--
function primePermutations() {
return true;
}
primePermutations();
--solutions--
function primePermutations() {
function arePermutations(num1, num2) {
const numStr1 = num1.toString();
let numStr2 = num2.toString();
if (numStr1.length !== numStr2.length) {
return false;
}
for (let i = 0; i < numStr1.length; i++) {
const index = numStr2.indexOf(numStr1[i]);
if (index === -1) {
return false;
}
numStr2 = numStr2.slice(0, index) + numStr2.slice(index + 1);
}
return true;
}
function isPrime(num) {
if (num < 2) {
return false;
} else if (num === 2) {
return true;
}
const sqrtOfNum = Math.floor(num ** 0.5);
for (let i = 2; i <= sqrtOfNum + 1; i++) {
if (num % i === 0) {
return false;
}
}
return true;
}
for (let num1 = 1000; num1 <= 9999; num1++) {
const num2 = num1 + 3330;
const num3 = num2 + 3330;
if (isPrime(num1) && isPrime(num2) && isPrime(num3)) {
if (arePermutations(num1, num2) && arePermutations(num1, num3)
&& num1 !== 1487) {
// concatenate and return numbers
return (num1 * 100000000) + (num2 * 10000) + num3;
}
}
}
return 0;
}