Oliver Eyton-Williams ee1e8abd87

feat(curriculum): restore seed + solution to Chinese (#40683 )

* feat(tools): add seed/solution restore script

* chore(curriculum): remove empty sections' markers

* chore(curriculum): add seed + solution to Chinese

* chore: remove old formatter

* fix: update getChallenges

parse translated challenges separately, without reference to the source

* chore(curriculum): add dashedName to English

* chore(curriculum): add dashedName to Chinese

* refactor: remove unused challenge property 'name'

* fix: relax dashedName requirement

* fix: stray tag

Remove stray `pre` tag from challenge file.

Signed-off-by: nhcarrigan <nhcarrigan@gmail.com>

Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>

2021-01-12 19:31:00 -07:00

900 B

Raw Blame History

id, title, challengeType, videoUrl, dashedName

id	title	challengeType	videoUrl	dashedName
5900f3b11000cf542c50fec4	问题69大欧拉	5		problem-69-totient-maximum

--description--

Euler的Totient函数φ（n）[有时称为phi函数]用于确定小于n的数字的数量，这些数字是n的相对素数。例如，如1,2,4,5,7和8都小于9且相对于9，φ（9）= 6。

n相对素数φ（n）n /φ（n）2 1 1 2 3 1,2 2 1.5 4 1,3 2 2 5 1,2,3,4 4 1.25 6 1,5 2 3 7 1,2， 3,4,5,6 6 1.1666 ... 8 1,3,5,7 4 2 9 1,2,4,5,7,8 6 1.5 10 1,3,7,9 4 2.5

可以看出，对于n≤10，n = 6产生最大n /φ（n）。找到n≤1,000,000的值，其中n /φ（n）是最大值。

--hints--

euler69()应该返回510510。

assert.strictEqual(euler69(), 510510);

--seed--

--seed-contents--

function totientMaximum() {

  return true;
}

totientMaximum();

--solutions--

// solution required

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