Oliver Eyton-Williams ee1e8abd87
feat(curriculum): restore seed + solution to Chinese (#40683)
* feat(tools): add seed/solution restore script

* chore(curriculum): remove empty sections' markers

* chore(curriculum): add seed + solution to Chinese

* chore: remove old formatter

* fix: update getChallenges

parse translated challenges separately, without reference to the source

* chore(curriculum): add dashedName to English

* chore(curriculum): add dashedName to Chinese

* refactor: remove unused challenge property 'name'

* fix: relax dashedName requirement

* fix: stray tag

Remove stray `pre` tag from challenge file.

Signed-off-by: nhcarrigan <nhcarrigan@gmail.com>

Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
2021-01-12 19:31:00 -07:00

53 lines
1.1 KiB
Markdown
Raw Blame History

This file contains ambiguous Unicode characters

This file contains Unicode characters that might be confused with other characters. If you think that this is intentional, you can safely ignore this warning. Use the Escape button to reveal them.

---
id: 5900f3b41000cf542c50fec7
title: 关卡 72分数计数
challengeType: 5
forumTopicId: 302185
dashedName: problem-72-counting-fractions
---
# --description--
考虑形如 `n`/`d` 的分数,其中 n 和 d 均为正整数。如果 `n`&lt;`d`,且最大公约数 HCF(`n`,`d`)=1则该分数被称为最简真分数。
如果我们将 `d` ≤ 8 的最简真分数构成的集合按大小升序列出,将得到:
<div style='text-align: center;'>1/8, 1/7, 1/6, 1/5, 1/4, 2/7, 1/3, 3/8, 2/5, 3/7, 1/2, 4/7, 3/5, 5/8, 2/3, 5/7, 3/4, 4/5, 5/6, 6/7, 7/8</div>
可以看出该集合中共有 21 个元素。
`d` ≤ 1,000,000 的最简真分数构成的集合中共有多少个元素。
# --hints--
`countingFractions()` 应该返回一个数字。
```js
assert(typeof countingFractions() === 'number');
```
`countingFractions()` 应该返回 303963552391。
```js
assert.strictEqual(countingFractions(), 303963552391);
```
# --seed--
## --seed-contents--
```js
function countingFractions() {
return true;
}
countingFractions();
```
# --solutions--
```js
// solution required
```