* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
67 lines
1005 B
Markdown
67 lines
1005 B
Markdown
---
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id: 597b2b2a2702b44414742771
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title: 阶乘
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challengeType: 5
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videoUrl: ''
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dashedName: factorial
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---
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# --description--
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<p>编写一个函数来返回一个数字的阶乘。 </p><p>一个数字的因子由下式给出: </p> N! = n \*(n-1)\*(n-2)\* ..... \* 1 <p>例如:3! = 3 * 2 * 1 = 6 4! = 4 * 3 * 2 * 1 = 24 </p><p>注意:0! = 1 </p>
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# --hints--
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`factorial`是一种功能。
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```js
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assert(typeof factorial === 'function');
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```
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`factorial(2)`应该返回一个数字。
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```js
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assert(typeof factorial(2) === 'number');
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```
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`factorial(3)`应该返回6.“)
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```js
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assert.equal(factorial(3), 6);
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```
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`factorial(3)`应返回120.“)
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```js
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assert.equal(factorial(5), 120);
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```
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`factorial(3)`应返回3,628,800。“)
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```js
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assert.equal(factorial(10), 3628800);
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```
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# --seed--
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## --seed-contents--
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```js
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function factorial(n) {
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}
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```
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# --solutions--
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```js
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function factorial(n) {
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let sum = 1;
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while (n > 1) {
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sum *= n;
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n--;
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}
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return sum;
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}
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```
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