* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
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id, title, challengeType, videoUrl, dashedName
id | title | challengeType | videoUrl | dashedName |
---|---|---|---|---|
59637c4d89f6786115efd814 | Hofstadter Q序列 | 5 | hofstadter-q-sequence |
--description--
Hofstadter Q序列定义为:
$ Q(1)= Q(2)= 1,\\ Q(n)= Q \ big(nQ(n-1)\ big)+ Q \ big(nQ(n-2)),\ quad n> 2. $
它定义为Fibonacci序列 ,但Fibonacci序列中的下一个术语是前两个术语的总和,在Q序列中,前两个术语告诉您在Q序列中返回多远以找到两个数字总结以制作序列的下一个术语。
任务:将Hofstadter Q Sequence方程实现为JavaScript--hints--
hofstadterQ
是一个函数。
assert(typeof hofstadterQ === 'function');
hofstadterQ()
应该返回integer
assert(Number.isInteger(hofstadterQ(1000)));
hofstadterQ(1000)
应该返回502
assert.equal(hofstadterQ(testCase[0]), res[0]);
hofstadterQ(1500)
应该返回755
assert.equal(hofstadterQ(testCase[1]), res[1]);
hofstadterQ(2000)
应该返回1005
assert.equal(hofstadterQ(testCase[2]), res[2]);
hofstadterQ(2500)
应该返回1261
assert.equal(hofstadterQ(testCase[3]), res[3]);
--seed--
--after-user-code--
const testCase = [1000, 1500, 2000, 2500];
const res = [502, 755, 1005, 1261];
--seed-contents--
function hofstadterQ(n) {
return n;
}
--solutions--
function hofstadterQ (n) {
const memo = [1, 1, 1];
const Q = function (i) {
let result = memo[i];
if (typeof result !== 'number') {
result = Q(i - Q(i - 1)) + Q(i - Q(i - 2));
memo[i] = result;
}
return result;
};
return Q(n);
}